【发布时间】:2017-02-21 09:26:16
【问题描述】:
大家好,我已经开始(我真的是新手)使用 php 使用 rabbitMQ 进行一些编码。
目前,我刚刚在 Rabbitmq 网站上测试了examples。 他们工作。 问题是,如果我在启动消费者之前向生产者发送一些消息,后者将不会接收以前的消息。它只接收从它开始时发送的消息。 那么我真的必须总是先启动生产者吗? 有没有办法实现一个队列,等待消费者可用后再刷新消息?
或者代码可能需要额外的设置?
感谢您的帮助
(rabbitMQ教程的PHP代码)
生产者.php
require_once __DIR__ . '/vendor/autoload.php';
use PhpAmqpLib\Connection\AMQPStreamConnection;
use PhpAmqpLib\Message\AMQPMessage;
$connection = new AMQPStreamConnection('localhost', 5672, 'guest', 'guest');
$channel = $connection->channel();
$channel->exchange_declare('direct_logs', 'direct', false, false, false);
$severity = isset($argv[1]) && !empty($argv[1]) ? $argv[1] : 'info';
$data = implode(' ', array_slice($argv, 2));
if(empty($data)) $data = "Hello World!";
$msg = new AMQPMessage($data);
$channel->basic_publish($msg, 'direct_logs', $severity);
echo " [x] Sent ",$severity,':',$data," \n";
$channel->close();
$connection->close();
?>
消费者: receive_logs_direct.php 的代码:
<?php
require_once __DIR__ . '/vendor/autoload.php';
use PhpAmqpLib\Connection\AMQPStreamConnection;
$connection = new AMQPStreamConnection('localhost', 5672, 'guest', 'guest');
$channel = $connection->channel();
$channel->exchange_declare('direct_logs', 'direct', false, false, false);
list($queue_name, ,) = $channel->queue_declare("", false, false, true, false);
$severities = array_slice($argv, 1);
if(empty($severities )) {
file_put_contents('php://stderr', "Usage: $argv[0] [info] [warning] [error]\n");
exit(1);
}
foreach($severities as $severity) {
$channel->queue_bind($queue_name, 'direct_logs', $severity);
}
echo ' [*] Waiting for logs. To exit press CTRL+C', "\n";
$callback = function($msg){
echo ' [x] ',$msg->delivery_info['routing_key'], ':', $msg->body, "\n";
};
$channel->basic_consume($queue_name, '', false, true, false, false, $callback);
while(count($channel->callbacks)) {
$channel->wait();
}
$channel->close();
$connection->close();
?>
【问题讨论】:
-
有什么代码不起作用?
-
我刚刚使用了RabbitMQ website中的代码,它可以工作......问题是生产者必须在消费者之前运行,以便消费者可以接收所有消息
标签: php rabbitmq message-queue