【发布时间】:2015-12-29 19:39:44
【问题描述】:
我正在尝试侦听错误队列以处理失败的消息,但我似乎无法让 MassTransit 不对我希望它在配置中侦听的消息设置绑定。配置如下,使用的是 MassTransit v3:
var hostAddress = new Uri("rabbitmq://localhost/");
var username = "guest";
var password = "guest";
_busControl = MassTransit.Bus.Factory.CreateUsingRabbitMq(configurator =>
{
var host = configurator.Host(hostAddress, h =>
{
h.Username(username);
h.Password(password);
});
configurator.ReceiveEndpoint(host, "myqueue_error",
endpointConfigurator =>
{
endpointConfigurator.Handler<SomeMessage>(context =>
{
return Console.Out.WriteLineAsync("Woop");
});
});
});
在上面的示例中,它将为发布SomeMessage 的任何内容设置绑定,并将它们定向到myqueue_error,我只希望消息进入此队列,该队列已从失败的服务转发。有没有办法使用队列中的消息,但告诉 MassTransit 不要为它们绑定?
更新 - 潜在的解决方案
似乎我不需要设置 ReceiveEndpoint,但我可以重命名控制总线以接受我关心的消息,然后这将能够处理这些消息,而无需为消息创建交换绑定。
以下是修改后的代码,不确定这是否是一种理想的方式,但它有效
var hostAddress = new Uri("rabbitmq://localhost/");
var username = "guest";
var password = "guest";
_busControl = MassTransit.Bus.Factory.CreateUsingRabbitMq(configurator =>
{
configurator.Host(hostAddress, h =>
{
h.Username(username);
h.Password(password);
});
// We need to make the queue look like the error queue
configurator.BusQueueName = $"{_queue}_error";
configurator.Durable = true;
configurator.AutoDelete = false;
configurator.SetQueueArgument("x-expires", null);
});
var connectHandle = _busControl.ConnectHandler<SomeMessage>(context => Console.Out.WriteLineAsync("Woop"));
_busHandle = _busControl.Start();
_busHandle.Ready.Wait();
// Wait
// Clean up
connectHandle.Disconnect();
_busHandle.Stop
【问题讨论】:
标签: c# .net rabbitmq masstransit message-bus