【发布时间】:2021-05-22 17:20:10
【问题描述】:
我正在尝试访问在main.js 中声明的Vue.prototype.$firebase 的全局对象
import Vue from "vue";
import App from "./App.vue";
import router from "./router";
import VueTailwind from "vue-tailwind";
import { FirebaseApp } from "@/firebase/firebase";
//Style
import "@/assets/styles/app.css";
import settings from "@/assets/styles/Tailwind.js";
FirebaseApp.auth().onAuthStateChanged((user)=>{
Vue.prototype.$user = user;
})
//Vue
Vue.config.productionTip = false;
Vue.use(VueTailwind, settings);
Vue.prototype.$firebase = FirebaseApp;
new Vue({
router,
render: h => h(App)
}).$mount("#app");
Login 组件内部
<script>
export default {
name: "Login",
mounted: function () {
this.submit();
},
methods: {
submit() {
let login = document.getElementById("login");
login.addEventListener(
"submit",
function (event) {
event.preventDefault();
const email = login.email.value;
const password = login.password.value;
this.$firebase
.auth()
.signInWithEmailAndPassword(email, password)
.then((user) => {
console.log(user)
this.$router.replace('/')
})
.catch((error) => {
console.log(error);
});
},
true
);
},
},
};
</script>
但我得到TypeError: Cannot read property 'auth' of undefined,与this.$router 相同。
但是在.addEvenListener 之外实例化对象可以很好地打印并让我可以通过let signIn 访问,但这不是我想要的行为,相反,我想在login 和dashboard 之间“自动”路由onAuthStateChange 通过使用 Vue.prototype.$firebase 而不是本地实例化进行登录:
<script>
export default {
name: "Login",
mounted: function () {
this.submit();
},
methods: {
submit() {
let login = document.getElementById("login");
let signIn = this.$FirebaseApp;
let onLogin = this.$router;
login.addEventListener(
"submit",
function (event) {
event.preventDefault();
const email = login.email.value;
const password = login.password.value;
signIn
.auth()
.signInWithEmailAndPassword(email, password)
.then((user) => {
console.log(user)
onLogin.replace('/')
})
.catch((error) => {
console.log(error);
});
},
true
);
},
},
};
</script>
访问Vue.prototype.$firebase 的正确方法是什么?为什么它有这样的范围限制?
【问题讨论】:
标签: javascript vue.js ecmascript-6 vuejs2 vue-component