【发布时间】:2013-12-17 11:40:45
【问题描述】:
我已经登录,它设置了一个带有估算电子邮件地址值的 cookie,因此在 global.php 文件中,它使用以下方式存储了一个用户数据数组:
$email = $_COOKIE["PeopleHub"];
$getuserdata = mysqli_query($con, "SELECT * FROM Earth WHERE email='$email'");
$userdata = mysqli_fetch_array($getuserdata, MYSQLI_ASSOC);
cookie 没有设置,我知道这是因为我制作了一个测试文件:
echo $_COOKIE["PeopleHub"];
它只是做了一个空白页。
登录代码(设置cookie的地方):
<?php
include "global.php";
?>
<h2>Login</h2>
<?php
echo "We currently have <b>" . $usercount . "</b> members, <b>" . $onlinecount . "</b> of which are online. ";
?>
<br>
<br>
<?php
if(isset($_POST["email"])){
$email = $_POST["email"];
$password = sha1($_POST["password"]);
$check = mysqli_query($con, "SELECT * FROM Earth WHERE `email`='$email' AND `password`='$password'");
$check = mysqli_num_rows($check);
if($check == 1){
setcookie("PeopleHub", $email, 0, '/');
echo "We logged you in!";
}
else {
echo "We couldn't log you in!";
}
}
?>
<form action="<?php echo $_SERVER['REQUEST_URI']; ?>" method="post">
Email <input name="email" placeholder="Email Address" required="" type="text"><br>
Password <input name="password" placeholder="Password" required="" type="password"><br>
<input type="reset" value="Start Over">
<input type="submit" value="Login">
</form>
【问题讨论】:
-
只是在这里说,但你应该清理你的数据,因为你放在那里的代码非常容易受到 SQLI 攻击
-
不,序列化数据不是一个伟大的选项。考虑准备好的语句或 PDO。