【发布时间】：2016-11-10 01:26:28
【问题描述】：
我正在设计一个房地产网站。我的网站上有很多广告，感谢我的朋友 Arsh Singh，我在每个帖子上创建了一个“收藏”或“保存”按钮，该按钮将根据 cookie 将所选页面标题保存在特定页面中，供用户查看帖子当他或她想要的时候。
现在我想在用户点击“添加到收藏夹”时将广告的 id 发送到收藏页面，因此基于 id 我可以从数据库中获取某些广告数据。
我可以这样做吗？如何？这是我当前的代码，它只能将页面标题发送到最喜欢的页面。有什么想法吗？
<!DOCTYPE html>
<html>
<head>
<title>New page name</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.2/jquery.min.js"></script>
<script src=favoritecookie.js></script>
</head>
<body>
<a href="javascript:void(0);" id="addTofav">Add me to fav</a>
<ul id="appendfavs">
</ul>
<?php
error_reporting(0);
include("config.php");
(is_numeric($_GET['ID'])) ? $ID = $_GET['ID'] : $ID = 1;
$result = mysqli_query($connect,"SELECT*FROM ".$db_table." WHERE idhome = $ID");
?>
<?php while($row = mysqli_fetch_array($result)):
$price=$row['price'];
$rent=$row['rent'];
$room=$row['room'];
$date=$row['date'];
?>
<?php
echo"price";
echo"room";
echo"date";
?>
<?php endwhile;?>
</body>
</html>//favoritecookie.js
/*
* Create cookie with name and value.
* In your case the value will be a json array.
*/
function createCookie(name, value, days) {
var expires = '',
date = new Date();
if (days) {
date.setTime(date.getTime() + (days * 24 * 60 * 60 * 1000));
expires = '; expires=' + date.toGMTString();
}
document.cookie = name + '=' + value + expires + '; path=/';
}
/*
* Read cookie by name.
* In your case the return value will be a json array with list of pages saved.
*/
function readCookie(name) {
var nameEQ = name + '=',
allCookies = document.cookie.split(';'),
i,
cookie;
for (i = 0; i < allCookies.length; i += 1) {
cookie = allCookies[i];
while (cookie.charAt(0) === ' ') {
cookie = cookie.substring(1, cookie.length);
}
if (cookie.indexOf(nameEQ) === 0) {
return cookie.substring(nameEQ.length, cookie.length);
}
}
return null;
}
/*
* Erase cookie with name.
* You can also erase/delete the cookie with name.
*/
function eraseCookie(name) {
createCookie(name, '', -1);
}
var faves = new Array();
function isAlready(){
var is = false;
$.each(faves,function(index,value){
if(this.url == window.location.href){
console.log(index);
faves.splice(index,1);
is = true;
}
});
return is;
}
$(function(){
var url = window.location.href; // current page url
$(document.body).on('click','#addTofav',function(e){
e.preventDefault();
var pageTitle = $(document).find("title").text();
if(isAlready()){
} else {
var fav = {'title':pageTitle,'url':url};
faves.push(fav);
}
var stringified = JSON.stringify(faves);
createCookie('favespages', stringified);
location.reload();
});
$(document.body).on('click','.remove',function(){
var id = $(this).data('id');
faves.splice(id,1);
var stringified = JSON.stringify(faves);
createCookie('favespages', stringified);
location.reload();
});
var myfaves = JSON.parse(readCookie('favespages'));
if(myfaves){
faves = myfaves;
} else {
faves = new Array();
}
$.each(myfaves,function(index,value){
var element = '<li class="'+index+'"><h4>'+value.title+'</h4> <a href="'+value.url+'">Open page</a> '+
'<a href="javascript:void(0);" class="remove" data-id="'+index+'">Remove me</a>';
$('#appendfavs').append(element);
});
});【问题讨论】：
-
只是对关于 SQL 注入的警告的快速说明，您最好检查
is_numeric($_GET['ID'])，但您也应该始终至少使用mysqli_real_escape_string()php.net/manual/en/mysqli.real-escape-string.php。并且可以这样写$ID = is_numeric($_GET['ID']) ? $_GET['ID'] : 1;:)
标签： javascript php