【发布时间】:2023-03-23 23:06:01
【问题描述】:
我正在学习如何在Vuejs 中呈现HTML 内容我正在尝试构建一个从render 函数生成的小型输入组件。它看起来像这样:
export default {
name: "nits-input",
methods: {
},
props: {
label: String,
hint: String,
error: String,
placeholder: String
},
render (createElement) {
//Help action text
let helpText = this.hint ? createElement('span', { class: 'm-form__help' }, this.hint) : ''
//Error Text
let errorText = this.error ? createElement('span', { class: 'm--font-danger' }, this.error) : ''
return createElement('div', { class: ''}, [
createElement('label', this.label),
createElement('input', {
class: 'form-control m-input',
attrs: { type: this.type, placeholder: this.placeholder },
domProps: { value: self.value},
on: {
input: function (event) {
this.$emit('input', event.target.value)
}
}
}),
helpText, errorText
])
}
}
在调用此组件时,我正在执行以下操作:
<div class="form-group m-form__group">
<nits-input
label="Email Address"
type="email"
hint="We'll never share your email with anyone else."
placeholder="Enter email"
v-model="email"
>
</nits-input>
</div>
<div class="form-group m-form__group">
<nits-input
label="Password"
type="password"
placeholder="Enter password"
v-model="password"
>
</nits-input>
</div>
我希望将值存储到 v-model 中,以检查值是否设置正确我正在使用监视功能
watch: {
email () {
console.log('Email v-model defined as '+this.email)
},
password() {
console.log('Password v-model defined as '+this.password)
}
}
但这总是给我错误:
未捕获的类型错误:无法读取 null 的属性“$emit”
我从This VueJS Documentation Link 获取了参考资料。帮我解决这个问题。谢谢。
【问题讨论】:
标签: javascript html vue.js vuejs2 vue-component