【问题标题】:How to ignore update or insert join if NULL value如果 NULL 值,如何忽略更新或插入连接
【发布时间】:2019-09-29 15:33:30
【问题描述】:

我有一个实体 bean,它与 @ManyToOne 的关系在一个列上加入。

@Entity
@Table(name = "work_order")
public class WorkOrder implements Serializable {

private static final long serialVersionUID = 1L;

@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sequenceGenerator")
@SequenceGenerator(name = "sequenceGenerator")
private Long id;

@NotNull
@Column(name = "id_order", nullable = false)
private String idOrder;

@Column(name = "description")
private String description;

@Enumerated(EnumType.STRING)
@Column(name = "status")
private StatusOrder status;

@Column(name = "creation_date")
private Instant creationDate;

@Column(name = "closing_date")
private Instant closingDate;

@Column(name = "client_id")
private Long clientId;

@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST) @NotFound (action = NotFoundAction.IGNORE)
@Fetch(FetchMode.JOIN)
@JoinColumn(name = "account",  insertable = false, updatable = false, nullable = true)
private AnagraficaClienti account;

还有第二个实体

@Entity
@Table(name = "es_account")
public class AnagraficaClienti implements Serializable {

private static final long serialVersionUID = 1L;


// da rimettere a @NotNull 
@Column(name = "fk_cod_azienda", nullable = true)
private String fk_cod_azienda;
@Id
@NotNull
@Column(name = "account", nullable = false)
private String account;
// da rimettere a @NotNull
@Column(name = "tipo_cli_for", nullable = true)
private String tipoClienteFornitore;

@Column(name = "tipo_account", nullable = true)
private String tipoAccount;
....

“es_account”表具有三个不可为空的主键(fk_cod_azienda、account、tipo_cli_for),与“work_order”表的关系是按帐户列。

我的问题是,有时用户可能会使用空帐户值插入或更新 WorkOrder,而 AnagraficaClienti 实体无法避免这种情况,因为它需要一个非空(且不重复)值。

当帐户为空时,是否有任何方法可以绕过与 AnagraficaClienti 的联接?

【问题讨论】:

  • 只需将关系移动到 AnagraficaClienti 类并更改为 @OneToMany。使关系可为空。当您只想插入 WorkOrder 时,请执行此操作。当您要创建关系时,将托管实体 WorkOrder 添加到工作订单列表中,该列表由相应的 AnagraficaClienti 拥有
  • @thanhngo 您的意思是更改在 AnagraficaClienti 中使用 OneToMany 注释创建与 WorkOrder 的关系吗?请用代码做一个例子吗
  • 请看下面我的回答

标签: java hibernate jpa


【解决方案1】:

在我看来,@ManyToOne 由于创建了冗余关系而违反了 OOP 设计原则。相反,我总是使用相关实体列表创建 @OneToMany 关系。要将关系指定为可为空,只需在 @JoinColumn 中添加 nullable=true 属性。对于 @ManyToOne,您必须指定属性 optional=true。让我们试试看它是否有效。

工单

@Entity
@Table(name = "work_order")
public class WorkOrder implements Serializable {

private static final long serialVersionUID = 1L;

@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sequenceGenerator")
@SequenceGenerator(name = "sequenceGenerator")
private Long id;

@NotNull
@Column(name = "id_order", nullable = false)
private String idOrder;

@Column(name = "description")
private String description;

@Enumerated(EnumType.STRING)
@Column(name = "status")
private StatusOrder status;

@Column(name = "creation_date")
private Instant creationDate;

@Column(name = "closing_date")
private Instant closingDate;

@Column(name = "client_id")
private Long clientId;

AnagraficaClienti

@Entity
@Table(name = "es_account")
public class AnagraficaClienti implements Serializable {

private static final long serialVersionUID = 1L;


// da rimettere a @NotNull 
@Column(name = "fk_cod_azienda", nullable = true)
private String fk_cod_azienda;
@Id
@NotNull
@Column(name = "account", nullable = false)
private String account;
// da rimettere a @NotNull
@Column(name = "tipo_cli_for", nullable = true)
private String tipoClienteFornitore;

@Column(name = "tipo_account", nullable = true)
private String tipoAccount;

@OneToMany(cascade = {CascadeType.PERSIST, CascadeType.MERGE} )
@JoinColumn(name = "account", nullable = true)
private List<WorkOrder> workOrders;

当您想将工单插入数据库时​​:

workOrderRepository.save(workOrder);

当你想建立关系时:

AnagraficaClienti client = anagraficaClientiRepository.findById(...);
client.getWorkOrders().add(newWorkOrder);

【讨论】:

  • @puyabahrani 你能把我的答案标记为正确吗?
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