Reference.update 失败：第一个参数包含属性中的函数？

Question

我在尝试创建一个简单的云功能时遇到以下错误，该功能在 RD 上检测到类似，然后将广告发布到用户时间轴。

如何修复该功能？我做错了什么？

---

（以下 2 个错误来自 Firebase 云函数控制台）

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获取喜欢的用户名时出错：错误：Reference.update 失败：第一个参数包含属性“UserFYP.Bke7CYXP31dpyKdBGsiMOEov2q43.0PMdzaOyYBejf1Gh6Pk1RRA5WNJ2.postID.node_.children_.comparator_”中的函数，内容 = 函数 NAME_COMPARATOR（左，右）{

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TypeError：无法在 ServerResponse.send (/workspace/node_modules/express/lib/response) 处读取 ServerResponse.json (/workspace/node_modules/express/lib/response.js:257:20) 处未定义的属性“get” .js:158:21) 在 likerUIDRef.once.then.catch.error (/workspace/lib/index.js:669:52) 在 process._tickCallback (internal/process/next_tick.js:68:7)

相关打字稿：

 function addPersonalizedFYPPosts(whoLikes: string, postUID: string, postID: string) {
      
      //need to use data to fetch my latest likes
      //then I use the likers data to add the new post to his fypTimeline

      const ref = admin.database().ref(`Likes/${postUID}/${postID}/media1`);
      return ref.once("value") 
      .then(snapshot => {

        //use snapshot to get the my latest like ??
        //Now with this ssnapshot we see other people who liked the same post this liker has. get one of their UIDs and see what else they liked add that to thte likers timeline. 

        var i2 = 0

        snapshot.forEach((theChild) => {

          if (i2 == 0) {

            let uid = theChild.key
          
            //do what you want with the uid
  
            //const userWhoAlsoLiked = snapshot.forEach
  
            const likerUIDRef = admin.database().ref(`YourLikes/${uid}`);
            likerUIDRef.once("value")
            .then(snap =>{
              //const username = snap.val()
              
              var i = 0
              snap.forEach((child) => {
                //UserFYP
                if (i == 0) {
                  let timelineID = child.key;
                  let timeStamp = child.child("timeStamp");
                  let newPostID = child.child("postID");
                  let postUid = child.child("uid");
    
                  //admin.database().ref(`UserFYP/${whoLikes}/${timelineID}/`).update(["":""])
                  admin.database().ref(`UserFYP/${whoLikes}/${timelineID}/`).set({"postID": newPostID, "uid": postUid, "timeStamp": timeStamp})
                  .then(slap =>{
                    console.log("Success updating user FYP: " )
                    return Promise.resolve();
                  })
                  .catch(error => {
                    console.log("Error fetching likers username: " + error)
                    response.status(500).send(error);
                  })
                  i++;
                }
                // return;
              })
              
            })
            .catch(error => {
              console.log("Error fetching likers username: " + error)
              response.status(500).send(error)
            })
            
            return;
            
            i2++;
          }
      })

      })
      .catch(error => {
        console.log("The read failed: " + error)
        response.status(500).send(error)
      })  

    }

export const onPostLike = functions.database
.ref('/Likes/{myUID}/{postID}/media1/{likerUID}')
.onCreate((snapshot, context) => {
  const uid = context.params.likerUID
  const postID = context.params.postID
  const myUID = context.params.myUID
  //addNewFollowToNotif(uid, followerUID)

  return addPersonalizedFYPPosts(uid,myUID,postID);
})

Answer 1

在DataSnapshot 上调用child() 会给您另一个DataSnapshot。所以：

  snap.forEach((child) => {
    //UserFYP
    if (i == 0) {
      let timelineID = child.key;
      let timeStamp = child.child("timeStamp");
      let newPostID = child.child("postID");
      let postUid = child.child("uid");

在此代码中，您的局部变量是快照，其中包含 a.o.访问它们的功能。由于您只能将 JSON 写入数据库，因此快照会被拒绝。

您可能正在寻找的是：

  snap.forEach((child) => {
    //UserFYP
    if (i == 0) {
      let timelineID = child.key;
      let timeStamp = child.child("timeStamp").val();
      let newPostID = child.child("postID").val();
      let postUid = child.child("uid").val();