PostgreSQL，函数使用？答案

【问题标题】：PostgreSQL, function use?PostgreSQL，函数使用？
【发布时间】：2011-12-31 01:35:25
【问题描述】：

我有这样的功能：

CREATE OR REPLACE FUNCTION f_insert_account(usernames character varying, passwds  
character varying, identitass integer, jeniss smallint, statuss smallint, cnames 
character varying, unames character varying)
RETURNS character varying AS
$BODY$
DECLARE
iduserx int4;
usernamex varchar;
er int2:=0;
pesan varchar:='';
BEGIN
insert into t_account(username,passwd,identitas,jenis,status,cname,uname)
values(usernamex,f_encr(passwds),identitass,jeniss,statuss,cnames,unames);
RETURN pesan;
END;
$BODY$
LANGUAGE 'plpgsql' VOLATILE;
ALTER FUNCTION f_insert_account(usernames character varying, passwds character 
varying, identitass integer, jeniss smallint, statuss smallint, cnames character 
varying, unames character varying) OWNER TO postgres;

GRANT EXECUTE ON FUNCTION f_insert_account(usernames character varying, passwds 
character varying, identitass integer, jeniss smallint, statuss smallint, cnames  
character varying, unames character varying) TO public;

GRANT EXECUTE ON FUNCTION f_insert_account(usernames character varying, passwds 
character varying, identitass integer, jeniss smallint, statuss smallint, cnames   
character varying, unames character varying) TO postgres;

然后我会这样使用：

select f_insert_account('dayat', 'dayat', 1, 1, 1, 'cname', 'uname')

总是出现这样的错误：错误：函数 f_insert_account("unknown", "unknown", integer, integer, integer, "unknown", "unknown") 不存在 SQL 状态：42883 提示：没有函数匹配给定的名称和参数类型。您可能需要添加显式类型转换。字符：8

为什么会这样？？？

谢谢，

达亚特

【问题讨论】：

您展示了f_insert_account() 的创建，然后抱怨f_account_sp() 的错误。请澄清。

标签： postgresql

【解决方案1】：

smallint 数据类型有点棘手，因为您需要转换这些：

select f_insert_account('dayat', 'dayat', 1, 1::smallint, 1::smallint, 'cname', 'uname')

如果您想避免这种情况，我建议您将函数定义更改为使用普通的旧 integer 类型。

【讨论】：