com.api.WebSecurityConfig 中的字段 myUserDetailsS​​ervice 需要一个 bean，但找到了 2 个

Question

完全错误： com.api.WebSecurityConfig 中的字段 myUserDetailsS​​ervice 需要一个 bean，但找到了 2 个：

• user1：在文件中定义 [/tools/tomcat/instances/webapps/api/WEB-INF/classes/com/api/jwt/users/test1.class]
• user2：在文件中定义 [/tools/tomcat/instances/webapps/api/WEB-INF/classes/com/api/jwt/users/test2.class]

我有以下课程：

Test1.java

@Service
@Component("user1")
public class Test1 implements UserDetailsService {

    @Value("${test1.username}")
    private String test1Username;

    @Value("${test1.password}")
    private String test1Password;

    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {

        if (username != null && username.equals(test1Username)) {
            return new User(username, test1Password, new ArrayList<>());
        } else {
            throw new UsernameNotFoundException("Username not found: " + username);
        }
    }

}

Test2.java

@Service
@Component("user2")
public class Test2 implements UserDetailsService {

    @Value("${test2.username}")
    private String test2Username;

    @Value("${test2.password}")
    private String test2Password;

    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {

        if (username != null && username.equals(test2Username)) {
            return new User(username, test2Password, new ArrayList<>());
        } else {
            throw new UsernameNotFoundException("Username not found: " + username);
        }
    }

}

SpringMainApplication.java

@EnableWebSecurity
class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private UserDetailsService myUserDetailsService;

    @Autowired
    private JwtRequestFilter jwtRequestFilter;

    @Autowired
    public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(myUserDetailsService);
    }

    @Bean
    public PasswordEncoder passwordEncoder() {
        return NoOpPasswordEncoder.getInstance();
    }

    @Override
    @Bean
    public AuthenticationManager authenticationManagerBean() throws Exception {
        return super.authenticationManagerBean();
    }

    @Override
    protected void configure(HttpSecurity httpSecurity) throws Exception {
        httpSecurity.csrf().disable()
            .authorizeRequests().antMatchers("/**/access-token").permitAll().
            anyRequest().authenticated().and().
            exceptionHandling().and().sessionManagement()
            .sessionCreationPolicy(SessionCreationPolicy.STATELESS);
        httpSecurity.addFilterBefore(jwtRequestFilter, UsernamePasswordAuthenticationFilter.class);
    }

}

JwtRequestFilter.java

@Component
public class JwtRequestFilter extends OncePerRequestFilter {

    @Autowired
    @Qualifier(value = "user1")
    private Test1 test1;

    @Autowired
    @Qualifier(value = "user2")
    private Test2 test2;

    @Override
    protected void doFilterInternal() throws ServletException, IOException {
        // SOME CODE
    }

我以为通过使用@Component和@Qualifier，我可以设置两个用户详细信息类，但似乎并非如此。

有什么我遗漏的或者在这个设计中是不可能的吗？

如果我创建另一个名为 MyUserDetailsService.java 的类，则编译工作正常，并且在各自的端点中访问正确的类。我只是不明白为什么MyUserDetailsService 必须存在并且我不能使用Test1 和Test2 作为用户类。

编辑：

Test1.java

@Service
@Component("myUserDetailsService")
public class Test1 implements UserDetailsService {

    @Value("${test1.username}")
    private String test1Username;

    @Value("${test1.password}")
    private String test1Password;

    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {

        if (username != null && username.equals(test1Username)) {
            return new User(username, test1Password, new ArrayList<>());
        } else {
            throw new UsernameNotFoundException("Username not found: " + username);
        }
    }

}

Test2.java

@Service
@Component("myUserDetailsService")
public class Test2 implements UserDetailsService {

    @Value("${test2.username}")
    private String test2Username;

    @Value("${test2.password}")
    private String test2Password;

    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {

        if (username != null && username.equals(test2Username)) {
            return new User(username, test2Password, new ArrayList<>());
        } else {
            throw new UsernameNotFoundException("Username not found: " + username);
        }
    }

}

SpringMainApplication.java

@EnableWebSecurity
class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    @Qualifier(value = "myUserDetailsService")
    private UserDetailsService myUserDetailsService;

    @Autowired
    private JwtRequestFilter jwtRequestFilter;

    @Autowired
    public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(myUserDetailsService);
    }

    @Bean
    public PasswordEncoder passwordEncoder() {
        return NoOpPasswordEncoder.getInstance();
    }

    @Override
    @Bean
    public AuthenticationManager authenticationManagerBean() throws Exception {
        return super.authenticationManagerBean();
    }

    @Override
    protected void configure(HttpSecurity httpSecurity) throws Exception {
        httpSecurity.csrf().disable()
            .authorizeRequests().antMatchers("/**/access-token").permitAll().
            anyRequest().authenticated().and().
            exceptionHandling().and().sessionManagement()
            .sessionCreationPolicy(SessionCreationPolicy.STATELESS);
        httpSecurity.addFilterBefore(jwtRequestFilter, UsernamePasswordAuthenticationFilter.class);
    }

}

JwtRequestFilter.java

@Component
public class JwtRequestFilter extends OncePerRequestFilter {

    @Autowired
    private Test1 test1;

    @Autowired
    private Test2 test2;

    @Override
    protected void doFilterInternal() throws ServletException, IOException {
        // SOME CODE
    }

这给了我以下错误：

org.springframework.beans.factory.BeanDefinitionStoreException: Failed to parse configuration class [com.api.SpringMainApplication];

nested exception is org.springframework.context.annotation.ConflictingBeanDefinitionException:

Annotation-specified bean name 'myUserDetailsService' for bean class [com.api.jwt.users.Test2DetailsService] conflicts with existing, non-compatible bean definition of same name and class [com.api.jwt.users.Test1DetailsService]

Answer 1

这些声明不需要限定符。 Spring 可以按类型注入它们，因为每种类型（Test1 和 Test2）都有一个匹配的 bean。

@Autowired
@Qualifier(value = "user1")
private Test1 test1;

@Autowired
@Qualifier(value = "user2")
private Test2 test2;

但是，您确实需要此声明的限定符，因为您有两个 UserDetailsService 实现，并且 spring 不知道要注入哪一个，从而导致错误。

@Autowired
private UserDetailsService myUserDetailsService;

编辑

在您更新的示例中，您定义了两个具有相同 bean id 的 bean

@Component("myUserDetailsService")
public class Test1 implements UserDetailsService {

@Component("myUserDetailsService")
public class Test2 implements UserDetailsService {

这会导致您看到的新错误（查看Spring documentation 可能会有所帮助）：

注解指定的 bean 名称 'myUserDetailsS​​ervice' 用于 bean 类 [com.api.jwt.users.Test2DetailsS​​ervice] 与现有冲突， 相同名称和类的不兼容 bean 定义 [com.api.jwt.users.Test1DetailsS​​ervice]

在您的示例中，拥有两个 UserDetailsService 实现并没有真正意义。您可以通过将它们组合成一个类来重构。