我认为这将是一个很好的解决方案：
const input = [{"name":"A", "points": 9},
{"name":"A", "points": 5},
{"name":"A", "points": 4},
{"name":"A", "points": 1},
{"name":"A", "points": 3},
{"name":"A", "points": 6},
{"name":"B", "points": 5},
{"name":"B", "points": 1},
{"name":"B", "points": 2},
{"name":"B", "points": 3}];
//this function will be passed to Array's "reduce" function, and will return the item with the lowest points
const reduceLowest = (lowest, current) => current.points < lowest.points ? current : lowest;
//this function receives an item and returns a new item with an additional "type" property
const addType = (item, typeToAdd) => { return { name : item.name, points : item.points, type : typeToAdd } };
//this function receives an array and returns another array with its two lowests items (typeA and typeB)
const returnTypeATypeB = (arr) => {
var lowestTypeA = arr
.reduce(reduceLowest) //gets the lowest item
;
var lowestTypeB = arr
.filter((item) => item != lowestTypeA) //removes the item that already is the lowest from the array
.reduce(reduceLowest) //gets the lowest item
;
//return an array containing the typeA and typeB items
return [ addType(lowestTypeA, "typeA"), addType(lowestTypeB, "typeB")];
};
const output =
returnTypeATypeB(
input.filter((item) => item.name === "A")
) //gets typeA and typeB from the items which contains the name "A"
.concat( //concat the previous list with..
returnTypeATypeB(
input.filter((item) => item.name === "B")
) //typeA and typeB from the items which contains the name "B"
);
console.log(output);
//prints..
// [ { name: 'A', points: 1, type: 'typeA' },
// { name: 'A', points: 3, type: 'typeB' },
// { name: 'B', points: 1, type: 'typeA' },
// { name: 'B', points: 2, type: 'typeB' } ]