升级到 gulp 4 后 gulp watch 出现问题

Question

链接到这个问题 = Gulp error: The following tasks did not complete: Did you forget to signal async completion?

当我尝试使用以下代码运行“watch”时，它会出错：

gulp.task('watch', async function() {
    var watchJs = gulp.watch(paths.js, ['scripts']),
        watchJson = gulp.watch(paths.json, ['json']),
        watchHtml = gulp.watch(paths.html, ['html']),
        watchCss = gulp.watch(paths.css, ['css']),
        watchFonts = gulp.watch(paths.fonts, ['fonts']),
        watchAssets = gulp.watch(paths.assets, ['assets']),

        onChanged = function(event) {
            console.log('File ' + event.path + ' was ' + event.type + '. Running tasks...');
        }

    watchJs.on('change', onChanged);
    watchJson.on('change', onChanged);
    watchHtml.on('change', onChanged);
    watchCss.on('change', onChanged);
    watchFonts.on('change', onChanged);
    watchAssets.on('change', onChanged);
});

错误提示：Error: watching src/js/**/*.js: watch task has to be a function (optionally generated by using gulp.parallel or gulp.series)

但我不知道如何解决这个问题。我尝试将异步放在 gulp.task('watch', async function() { 但这不起作用

Answer 1

改变

 var watchJs = gulp.watch(paths.js, ['scripts']),  // gulp v3 syntax

到

 var watchJs = gulp.watch(paths.js, gulp.serie('scripts')),  //  gulp v4 syntax

和你的其他人一样。查找从 gulp v3 到 v4 的迁移指南。