在递归函数中如何调用原始承诺解决方案

Question

我编写了以下 lambda 函数来从 API 中获取数据并将其放入数据库中。当 API 只返回一个页面时，这工作正常，但是在 resolve() 运行之前 > 1 页 parseData 运行，但永远不会触发“功能完成”日志。这是resolve() 没有解决我期望的承诺吗？

 exports.handler = async (event, context, callback) => {
  let db = await initDB(); // External function
  await api_get('users')
  console.log("Function finished");
  db.end()
  callback(null)

  function api_get(type, page = 1, count = 0, results = []) {
    return new Promise(async function(resolve, reject) {
        let uri = `https://api.com/v1/${type}`;
        request.get(uri + '?page=' + page, async (error, response, body) => {
          const data = JSON.parse(body);
          results.push(data.users)
          current_count = count + data.meta.count
          if (current_count < data.meta.total) {
              await api_get(type, page + 1, current_count, results);
          }
          else {
              await parseData(type, results)
              resolve()
          }
        });
    });
   }
   
  
   function parseData(type, data) {
      return new Promise(async function(resolve, reject) {
         switch (type) {
            case 'users':
               let users = [].concat(...data)
               let sql = ''
               for (const user of users) {
                  sql = sql + `INSERT INTO users (user_id) VALUES ('${user_id}');`
               }
               db.query(sql)
               .then( () => {
                  resolve()
               })
            break;
         }
      });
   }
 };

Answer 1

如果满足此条件，则不会调用 resolve()：

      if (current_count < data.meta.total) {
          // If execution go in this block, you are never calling "resolve()"
          await api_get(type, page + 1, current_count, results);
      }
      else {
          await parseData(type, results)
          resolve()
      }