【问题标题】:How to make a request wait for a previous request to complete?如何使请求等待先前的请求完成?
【发布时间】:2016-09-06 03:18:37
【问题描述】:

我正在尝试将 API 调用发送到 NodeJS 服务器。不幸的是,服务器(不是我制作的)不允许我进行异步调用。

我正在尝试找出一种方法,让每个请求都等待前一个请求完成后再发送。

这是我的代码:

var http = require('http');
var fs = require('fs');

// An object of options to indicate where to post to
var post_options = {
    host: 'localhost',
    port: '8080',
    path: '/api/scan',
    method: 'POST',
    headers: {
        'Content-Type': 'application/json'
    }
};
var array = ["ssl.com", "google.com", "hamzakhan.org"];
for (var i=0; i<array.length;i++) {
    //console.log(array[i]);
    var post_req = http.request(post_options, function(res) {
        res.setEncoding('utf8');
        var body = '';
        res.on('data', function(chunk) {
            body += chunk;
        });
        res.on('end', function() {
            body = JSON.parse(body);
            // Make sure it's working
            console.log(body.response.subject);
        });
    });

    var url = array[i];
    var catURL = { "url": url, "path": "/", "port": "443", "live_scan": "false", "advanced": "true" };
    post_req.write(JSON.stringify(catURL), function(err) {
        //console.log(err);
        post_req.end();
    });

}

我在想我可以在 for 循环中嵌套一个 while 循环,而 while 循环会有一个标志来指示 for 循环何时可以继续进行。

现在,当我将 url 的值硬编码为单个 url 时,此代码有效,因此我知道我成功发送和接收。

感谢所有/任何帮助!

【问题讨论】:

  • 而不是循环通过您的array 变量,例如,您可以从它的第一个元素开始,然后在您的res.on('end',function() { ... /* callback here */ ... }) 中放置一个回调来告诉您的程序每次都开始一个新请求响应结束,直到不再有请求发送。你怎么看?
  • 我如何开始一个新的请求?
  • 请参见下面基于您的代码的示例。请注意,我没有测试该示例。我只是添加了几行来说明我的建议。

标签: javascript node.js api rest asynchronous


【解决方案1】:
/**
 * Disclaimer: I did not test your code. I simply added a few
 * lines to illustrate my suggestion.
 */

var http = require('http');
var fs = require('fs');
var EventEmitter = require('events').EventEmitter;

// An object of options to indicate where to post to

var post_options = {
    host: 'localhost',
    port: '8080',
    path: '/api/scan',
    method: 'POST',
    headers: {
        'Content-Type': 'application/json'
    }
};

var array = ["ssl.com", "google.com", "hamzakhan.org"];
var emitter = new EventEmitter();
var counter = 0, n = array.length;

function PostRequest() {
    var post_req = http.request(post_options, function(res) {
        res.setEncoding('utf8');
        var body = '';
        res.on('data', function(chunk) {
            body += chunk;
        });
        res.on('end', function() {
            body = JSON.parse(body);
            // Make sure it's working
            console.log(body.response.subject);

            // ADD THE CALLBACK 
            // OR 
            // TRIGGER EVENT
            return emitter.emit('ResponseEnded');

        });
    });

    var url = array[counter];
    var catURL = { "url": url, "path": "/", "port": "443", "live_scan": "false", "advanced": "true" };
    post_req.write(JSON.stringify(catURL), function(err) {
        //console.log(err);
        post_req.end();
    });
}

emitter.on('ResponseEnded',function() {
    ++counter;
    if (counter < n) {
        PostRequest();
    }
    else {
        console.log('Nothing more request');
    }
});

// Start with the first request
PostRequest();

更新:这是做同样事情的另一种方式。

/**
 * Disclaimer: I did not test your code. I simply added a few
 * lines to illustrate my suggestion.
 */

var http = require('http');
var fs = require('fs');


// An object of options to indicate where to post to

var post_options = {
    host: 'localhost',
    port: '8080',
    path: '/api/scan',
    method: 'POST',
    headers: {
        'Content-Type': 'application/json'
    }
};

var array = ["ssl.com", "google.com", "hamzakhan.org"];
var counter = 0, n = array.length;

function PostRequest() {
    var post_req = http.request(post_options, function(res) {
        res.setEncoding('utf8');
        var body = '';
        res.on('data', function(chunk) {
            body += chunk;
        });
        res.on('end', function() {
            body = JSON.parse(body);
            // Make sure it's working
            console.log(body.response.subject);

            // THIS IS ANOTHER WAY OF DOING IT
            ++counter;
            if (counter < n) {
                /**
                 * This is were your start new 
                 * requests
                 */
                PostRequest();
            }
            else {
                console.log('Nothing more request');
            }            

        });
    });

    var url = array[counter];
    var catURL = { "url": url, "path": "/", "port": "443", "live_scan": "false", "advanced": "true" };
    post_req.write(JSON.stringify(catURL), function(err) {
        //console.log(err);
        post_req.end();
    });
}

// Start with the first request
PostRequest();

【讨论】:

  • 在这种情况下,你指的我的回调是什么?对不起,我对此很陌生。
  • 回调是您在任务完成后调用的函数。在这种情况下,我使用了一个事件发射器来更清楚地表明我们正在等待响应结束,然后再提交另一个请求;即,当请求结束时,我会发出一个名为“ResponseEnded”的事件,并且我在底部有一个该事件的事件侦听器列表。
  • 没关系。有效。出于某种原因,我以某种方式将counter &lt; n 切换为counter &gt; n
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