【问题标题】:Setting the DataContext for a ContextMenu from a ListView's ItemContainer?从 ListView 的 ItemContainer 为 ContextMenu 设置 DataContext?
【发布时间】:2011-07-29 13:23:15
【问题描述】:

我正在使用 mvvm 模式,我很难从 ListView 的 ItemContainerStyle 中弄清楚如何在 ContextMenu 上设置 DataContext。

我也不明白为什么 ListView.ContextMenu 和 ListView 的 GridView.ColumnHeaderContextMenu 可以从我的视图模型中看到属性和命令,而 ListView.ItemContainerStyle 中的 ContextMenu 却不能。

错误

System.Windows.Data 错误:40:BindingExpression 路径错误:在“对象”“货币”(HashCode=43406546)上找不到“AddMenuItem”属性。绑定表达式:路径=添加菜单项; DataItem='货币' (HashCode=43406546);目标元素是'ContextMenu'(名称='');目标属性是“ItemsSource”(类型“IEnumerable”)

查看

<!-- Removed styles for clarity. -->
<UserControl>

<!-- Add ElementSpy to the UserControl’s rsources -->
<UserControl.Resources>
    <framework:ElementSpy x:Key="spy" />
</UserControl.Resources>

<ListView ItemsSource="{Binding Currency}">

    <ListView.ItemContainerStyle>
        <Style TargetType="ListViewItem">
            <Setter Property="ContextMenu">
                <Setter.Value>
                    <!-- 'AddMenuItem' property not found on 'object' 'Currency' -->
                    <!-- ContextMenu ItemsSource="{Binding AddMenuItem}" / -->

                    <!-- Use the ElementSpy resource -->
                    <ContextMenu ItemsSource="{Binding Source={StaticResource spy}, Path=Element.DataContext.AddMenuItem}" />
                </Setter.Value>
            </Setter>
        </Style>
    </ListView.ItemContainerStyle>

    <ListView.ContextMenu>
        <!-- Works -->
        <ContextMenu ItemsSource="{Binding EditMenuItem}" />
    </ListView.ContextMenu>

    <ListView.View>
        <GridView>
            <GridView.ColumnHeaderContextMenu>
                <!-- Works -->
                <ContextMenu ItemsSource="{Binding SortMenuItem}" />
            </GridView.ColumnHeaderContextMenu>

            <GridViewColumn Header="Code"
                            DisplayMemberBinding="{Binding Path=Code}" />

            <GridViewColumn Header="Description"
                            DisplayMemberBinding="{Binding Path=Description}" />

            <GridViewColumn Header="Exchange Rate"
                            DisplayMemberBinding="{Binding Path=ExchangeRate}" />
        </GridView>

    </ListView.View>

</ListView>
</UserControl>

代码背后

[Export(ViewNames.CurrencyMasterView, typeof(IMasterView))]
[PartCreationPolicy(CreationPolicy.Shared)]
public partial class CurrencyMasterView
    : UserControl, IMasterView
{
    public CurrencyMasterView()
    {
        InitializeComponent();
    }

    [Import]
    private MasterViewModel ViewModel
    {
        set
        {
            this.DataContext = value;
        }
    }
}

视图模型

[Export(typeof(MasterViewModel))]
[PartCreationPolicy(CreationPolicy.NonShared)]
public class MasterViewModel
    : ViewModelBase
{
    [ImportingConstructor]
    public MasterViewModel(IGeneralController generalController, IRegionManager regionManager)
    {
    }

    public ObservableCollection<Currency> Currency
    {
        get
        {
            return this.currency;
        }

        set
        {
            if (this.currency != value)
            {
                this.currency = value;
                this.RaisePropertyChanged(() => this.Currency);
            }
        }
    }

    public List<MenuItemMvvm> SortMenuItem
    {
        get
        {
            return this.CreateSortMenuItem();
        }
    }

    public List<MenuItemMvvm> EditMenuItem
    {
        get
        {
            return this.CreateEditMenuItem();
        }
    }

    public List<MenuItemMvvm> AddMenuItem
    {
        get
        {
            return this.CreateAddMenuItem();
        }
    }

    private List<MenuItemMvvm> CreateEditMenuItem()
    {
        var menu = new List<MenuItemMvvm>();

        menu.Add(new MenuItemMvvm("_Edit")
        {
            Command = this.EditCommand,
            Icon = new Image
            {
                Source = new BitmapImage(new Uri("pack://application:,,,/POS.Modules.Core;component/Resources/Images/16X16/Edit.png"))
            }
        });

        menu.Add(new MenuItemMvvm("_Duplicate")
        {
            Command = this.DuplicateCommand,
            Icon = new Image
            {
                Source = new BitmapImage(new Uri("pack://application:,,,/POS.Modules.Core;component/Resources/Images/16X16/Copy.png"))
            }
        });

        menu.Add(new MenuItemMvvm("_Delete")
        {
            Command = this.DeleteCommand,
            Icon = new Image
            {
                Source = new BitmapImage(new Uri("pack://application:,,,/POS.Modules.Core;component/Resources/Images/16X16/Delete.png"))
            }
        });


        return menu;
    }

    // Other methods removed for clarity
}

【问题讨论】:

标签: wpf xaml listview binding


【解决方案1】:

这个问题帮助我弄清楚了。 WPF MenuItem.Command binding to ElementName results to System.Windows.Data Error: 4 : Cannot find source for binding with reference

我为其他遇到此问题的人更新了源代码。

为了快速参考,这就是我所做的。

添加 Josh Smith 的 ElementSpy 类。 Enable ElementName Bindings with ElementSpy

将 ElementSpy 添加到 UserControl 的 rsources。

<UserControl.Resources>
    <framework:ElementSpy x:Key="spy" />
</UserControl.Resources>

然后绑定到资源并使用 Element 属性绑定到 DataContext 和您选择的属性。

<ContextMenu ItemsSource="{Binding Source={StaticResource spy}, Path=Element.DataContext.AddMenuItem}" />

【讨论】:

    【解决方案2】:

    您必须在绑定中使用 RelativeSource 和 PlacementTarget。我使用以下 xaml 添加上下文菜单来设置数据网格列的可见性。

      <DataGrid.ContextMenu>
                    <ContextMenu>
                        <MenuItem Header="Spalten ein-/ausblenden">                           
                            <StackPanel>
                                <ItemsControl 
                                ItemsSource="{Binding RelativeSource={RelativeSource AncestorType=ContextMenu}, Path=PlacementTarget.Columns, Mode=OneWay}"
                                ItemTemplate="{StaticResource Visibility4DataGridColumns}"
                                ></ItemsControl>
                            </StackPanel>
                        </MenuItem>
                    </ContextMenu>
                </DataGrid.ContextMenu>
    

    【讨论】:

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