【发布时间】:2020-08-20 23:57:41
【问题描述】:
我正在使用 nodejs/mysql 执行 mysql 查询。
在第一个结果集之后,我将遍历结果集并查询第二个表。
1) 为什么“for”有效而“foreach”无效?实现我需要的正确循环方式是什么?
2) getImage 函数中的 item = { ...item, images: rows } 也不起作用,为什么?
3) 如何让console.log显示修改后的结果?如果我使用'await',console.log(rows) 应该会显示修改后的结果吧?
const getImages = async (item, key) => {
let sql = await connection.format('SELECT * from `images` WHERE id = ?', [item.id]);
const [ rows , fields ] = await connection.execute(sql);
item['images'] = rows
item = { ...item, images: rows } //'<-- this method doesn't work.
return item
}
let sql = await connection.format(`SELECT * from table ORDER BY a.listing_id LIMIT ?,?`, [0,10])
var [rows, fields] = await connection.execute(sql);
// rows.forEach(getImages) //'<-- this does not work when uncommented
// rows = rows.forEach(getImages) //'<-- this also does not work when uncommented.
for (let i = 0; i < rows.length; i++) { //'<-- but this works
rows[i] = await getImages(rows[i], i);
}
console.log(rows) //<----- this doesn't show modified results on terminal console
res.json(rows) //<----- browser can see the modified results on browser console
【问题讨论】:
标签: javascript mysql node.js