【发布时间】:2015-02-24 04:27:22
【问题描述】:
我已经在网站上遇到了几个问题,但我仍然看不出我在这里做错了什么,所以任何帮助都将不胜感激。
我收到了错误:
Organization (organizations) is not associated to User!
组织模型:
module.exports = function (sequelize, DataTypes) {
return sequelize.define('Organization', {
organizationID: {
primaryKey: true,
type: DataTypes.INTEGER(11),
allowNull: false,
},
name: {
type: DataTypes.STRING,
allowNull: false,
},
description: {
type: DataTypes.STRING,
allowNull: true,
}
},
{
tableName: "spa_vOrganization",
freezeTableName: true,
classMethods: {
associate: function (models) {
Organization.hasMany(models.User, {
as: 'users',
through: models.User_Tenant_Organization,
foreignKey: 'organizationID'
});
}
},
});
};
用户模型:
module.exports = function (sequelize, DataTypes) {
return sequelize.define('User', {
userID: {
primaryKey: true,
type: DataTypes.INTEGER(11),
allowNull: false,
},
password: {
type: DataTypes.STRING,
allowNull: false,
},
email: {
type: DataTypes.STRING,
allowNull: false,
}
},
{
tableName: "spa_User",
freezeTableName: true,
classMethods: {
associate: function(models) {
User.hasMany(models.Organization, { as: "organizations", through: models.User_Tenant_Organization, foreignKey: 'userID'});
}
}
}
);
};
矩阵表模型:
module.exports = function (sequelize, DataTypes) {
return sequelize.define('User_Tenant_Organization', {
userTenantOrganizationID: {
primaryKey: true,
type: DataTypes.INTEGER(11),
allowNull: false,
},
userID: {
type: DataTypes.INTEGER(11),
allowNull: false,
},
organizationID: {
type: DataTypes.INTEGER(11),
allowNull: false,
},
tenantID: {
type: DataTypes.INTEGER(11),
allowNull: false,
},
},
{
tableName: "spa_User_Tenant_Organization",
freezeTableName: true,
});
};
我要做的只是拉回一个用户,他们的组织急切地加载。这是我正在使用的:
models.User.findOne({where: {
email: body.email
}, include: [ {model:models.Organization, as: 'organizations'}]}).complete( function (err, user) {
// do something with the user
}
我已经尝试过在User 和Organization 上使用和不使用foreignKey 定义,没有任何区别。我显然误解了一些关于协会的事情。谁能告诉我哪里出错了?
【问题讨论】:
标签: node.js associations sequelize.js