动态生成列 mvvm

Question

我尝试制作一个动态生成列的 ListView。我使用 mvvm 模式。 我怎样才能实现这个？ 在这一刻，我只有静态列。

<ListView ItemsSource="{Binding ProblemProducts}"
                  Grid.Row="1" Grid.RowSpan="4" HorizontalAlignment="Left" VerticalAlignment="Top" Grid.Column="4">
            <ListView.View>
                <GridView>
                    <GridViewColumn Header="Spisujący" DisplayMemberBinding="{Binding _spisujacy}" Width="auto"/>
                    <GridViewColumn Header="Miejsce składowania" DisplayMemberBinding="{Binding MiejsceSkladowania}" Width="auto"/>
                    <GridViewColumn Header="Typ spisu" DisplayMemberBinding="{Binding _typSpisu}" Width="auto"/>
                    <GridViewColumn Header="Kod" DisplayMemberBinding="{Binding Kod}" width="auto"/>
                </GridView>
            </ListView.View>
        </ListView>

Answer 1

您可以使用转换器动态创建带有适当列的GridView。这是工作示例：

MainWindow.xaml

<Window x:Class="WpfApplication1.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" 
        xmlns:WpfApplication1="clr-namespace:WpfApplication1" 
        mc:Ignorable="d" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" 
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" 
        d:DesignHeight="189" d:DesignWidth="312" Width="300" Height="300">
    <Window.Resources>
        <WpfApplication1:ConfigToDynamicGridViewConverter x:Key="ConfigToDynamicGridViewConverter" />
    </Window.Resources>
    <ListView ItemsSource="{Binding Products}" View="{Binding ColumnConfig, Converter={StaticResource ConfigToDynamicGridViewConverter}}"/>    
</Window>

MainWindow.xaml.cs

using System.Collections.Generic;
using System.Windows;

namespace WpfApplication1
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();
            DataContext = new ViewModel();
        }
    }

    public class ViewModel
    {
        public ColumnConfig ColumnConfig { get; set; }
        public IEnumerable<Product> Products { get; set; }

        public ViewModel()
        {
            Products = new List<Product> { new Product { Name = "Some product", Attributes = "Very cool product" }, new Product { Name = "Other product", Attributes = "Not so cool one" } };
            ColumnConfig = new ColumnConfig { Columns = new List<Column> { new Column { Header = "Name", DataField = "Name" }, new Column { Header = "Attributes", DataField = "Attributes" } } };
        }
    }

    public class ColumnConfig
    {
        public IEnumerable<Column> Columns { get; set; }
    }

    public class Column
    {
        public string Header { get; set; }
        public string DataField { get; set; }
    }

    public class Product
    {
        public string Name { get; set; }
        public string Attributes { get; set; }
    }
}

ConfigToDynamicGridViewConverter.cs

using System;
using System.Globalization;
using System.Windows.Controls;
using System.Windows.Data;

namespace WpfApplication1
{
    public class ConfigToDynamicGridViewConverter : IValueConverter
    {
        public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
        {
            var config = value as ColumnConfig;
            if (config != null)
            {
                var gridView = new GridView();
                foreach (var column in config.Columns)
                {
                    var binding = new Binding(column.DataField);
                    gridView.Columns.Add(new GridViewColumn {Header = column.Header, DisplayMemberBinding = binding});
                }
                return gridView;
            }
            return Binding.DoNothing;
        }

        public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
        {
            throw new NotSupportedException();
        }
    }
}

Answer 2

感谢 Sergei，提供了一个了不起的答案。

我以稍微不同的形式使用它，因为我需要添加非文本数据类型的列。

因此，对 Sergei 答案的以下修改允许您在数据值上使用 ContentControl 包装器。然后将根据为每个单元格中的值定义的 DataTemplates 呈现它们。

如果使用 ContentControlDataField 而不是 TextDataField（最初是 DataField），则该列将被换行：

    public class ConfigToDynamicGridViewConverter : IValueConverter {
    public object Convert(object value, Type targetType, object parameter, CultureInfo culture) {
        var config = value as ColumnConfig;
        if (config != null) {
            var grdiView = new GridView();
            foreach (var column in config.Columns) {
                bool cc = !string.IsNullOrEmpty(column.ContentControlDataField);
                var binding = new Binding(cc ? column.ContentControlDataField : column.TextDataField);
                if (cc) {
                    var template = new DataTemplate();
                    var fact = new FrameworkElementFactory(typeof(ContentControl));
                    fact.SetBinding(ContentControl.ContentProperty, binding);
                    template.VisualTree = fact;
                    grdiView.Columns.Add(new GridViewColumn {Header = column.Header, CellTemplate = template});
                } else
                    grdiView.Columns.Add(new GridViewColumn {Header = column.Header, DisplayMemberBinding = binding});
            }
            return grdiView;
        }
        return Binding.DoNothing;
    }

    public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture) {
        throw new NotSupportedException();
    }
}

public class ColumnConfig {
    public IEnumerable<Column> Columns { get; set; }
}

public class Column {
    public string Header { get; set; }
    public string TextDataField { get; set; }
    public string ContentControlDataField { get; set; }
}