【发布时间】：2015-06-14 02:17:27
【问题描述】：
我是 C 编程的新手，我已经为需求规范编写了代码，但我一直遇到分段错误并且无法继续进行。 如果文件名是“code.c”并且它运行时出现未传递参数（文件名）的错误。但是如果文件名通过了，我们就会陷入分段错误。 任何帮助/建议将不胜感激。
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
struct _data
{
char *firstName;
char *lastName;
long number;
};
// SCAN FILE
int SCAN(FILE *(*stream))
{
*stream = fopen("inputFile.data", "r");
int ch = 0, lines = 0;
while (!feof(*stream))
{
ch = fgetc(*stream);
if (ch == '\n')
{
lines++;
}
}
return lines;
}
// LOAD FILE
struct _data *LOAD(FILE *stream, int size)
{
int i;
size_t chrCount;
char *text, *number, *firstName, *lastName;
struct _data *BlackBox;
if ((BlackBox = (struct _data*)calloc(size, sizeof(struct _data))) == NULL)
{
printf("ERROR - Could not allocate memory.\n");
exit(0);
}
rewind(stream);
for (i = 0; i < size; i++)
{
getline(&text, &chrCount, stream);
firstName = strtok(text, " ");
lastName = strtok(text, " ");
number = strtok(NULL, "\n");
// Allocate memory for name part of struct.
if ((BlackBox[i].firstName = (char*)calloc(strlen(firstName), sizeof(char))) == NULL)
{
printf("ERROR - Could not allocate memory.\n");
exit(0);
}
if ((BlackBox[i].lastName = (char*)calloc(strlen(lastName), sizeof(char))) == NULL)
{
printf("ERROR - Could not allocate memory.\n");
exit(0);
}
strcpy(BlackBox[i].firstName, firstName);
strcpy(BlackBox[i].lastName, lastName);
BlackBox[i].number = atol(number);
}
fclose(stream);
return BlackBox;
}
void SEARCH(struct _data *BlackBox, char *name, int size, int inputs)
{
int i;
int found = 0;
char *search = " ";
char *firstName;
char *lastName;
if (inputs == 2)
{
firstName = strtok(name, search);
lastName = strtok(NULL, search);
}
printf("*******************************************\n");
if (inputs == 2)
{
for (i = 0; i < size; i++)
{
if (!strcasecmp(firstName, BlackBox[i].firstName) && !strcasecmp(firstName, BlackBox[i].firstName))
{
printf("The name was found at the %d entry.\n", i);
found = 1;
break;
}
}
}
else
{
for (i = 0; i < size; i++)
{
if (!strcasecmp(firstName, BlackBox[i].firstName) || !strcasecmp(firstName, BlackBox[i].firstName))
{
printf("The name was found at the %d entry.\n", i);
found = 1;
break;
}
}
}
if (found == 0)
{
printf("The name was NOT found.\n");
}
printf("*******************************************\n");
}
// FREE MEMORY
void FREE(struct _data *BlackBox, int size)
{
int i;
for (i = 0; i < size; i++)
{
free(BlackBox[i].firstName);
free(BlackBox[i].lastName);
}
free(BlackBox);
BlackBox = NULL;
}
// MAIN
int main(int argv, char **argc)
{
int size;
FILE *stream;
struct _data *BlackBox;
// argv == 1 WORKS, Below message is printed.
if (argv == 1)
{
printf("*******************************************\n");
printf("* You must include a name to search for. *\n");
printf("*******************************************\n");
}
// argv == 2 DOES NOT WORK, Segmentation Fault.
if (argv == 2)
{
size = SCAN (&stream);
BlackBox = LOAD(stream, size);
SEARCH(BlackBox, argc[1], size, 1);
}
if (argv == 3)
{
size = SCAN(&stream);
BlackBox = LOAD(stream, size);
SEARCH(BlackBox, argc[2], size, 2);
}
return 0;
}
【问题讨论】：
-
你永远不会检查
fopen()是否成功！而while (!feof(file))总是错的。 -
您是否尝试在它崩溃时留下的核心文件上运行
pstack（假设您在系统上正确配置了核心转储设置），或者在 gdb 等调试器中运行它，所以当它崩溃了你可以学习#?当一个程序 segv 的第一件事你需要做的是找出它发生在哪一行。 -
实际上
pstack <core>可以在 Solaris 上工作，但在 Linux 上可能不行，但这应该是：gdb path/to/corefile/<core>(gdb) where(gdb) thread apply all bt -
if ((BlackBox[i].firstName = (char*)calloc(strlen(firstName),NUL +1 -
@iharob 我没有，因为文件在我身边，这不是企业代码。我确实理解这是错误的，但这是否会导致 SF 故障？
标签： c segmentation-fault argv argc