选择单选按钮后的 PySimpleGUI 文本框输出信息

Question

所以我现在要做的是，如果我单击其中一个单选按钮，则有关该方法的一些信息应自动显示在 GUI 中，但我似乎无法正确处理。 我想也许我可以通过使用 if 语句来完成它，但没有任何反应。

import PySimpleGUI as sg

# List for Radiobuttons
radio_choices = ["Method 1", "Method 2", "Method 3", "Method 4"]

layout = [[sg.Text("Choose Method")],
          *[[sg.Radio(text, 1), ] for text in radio_choices],
          [sg.Button("Start"), sg.Button("Stop"), sg.Button("Exit")]


          ]

window = sg.Window("Choose Method", layout, size=(350, 350))

while True:
    event, values = window.Read()

    
    if event == "Exit" or event == sg.WIN_CLOSED:
        break

    if event == radio_choices[0]:
        sg.Text("Method 1 description")
window.close()

Answer 1

试试这个：

import PySimpleGUI as sg

# List for Radiobuttons
radio_choices = ["Method 1", "Method 2", "Method 3", "Method 4"]

layout = [[sg.Text("Choose Method")],
          *[[sg.Radio(text, 1),sg.Text('this is ' + text ,key=text, visible=False) ] for text in radio_choices],
          [sg.Button("Start"), sg.Button("Stop"), sg.Button("Exit")]


          ]

window = sg.Window("Choose Method", layout, size=(350, 350))

while True:
    event, values = window.Read()

    print(event, values)
    if event == "Exit" or event == sg.WIN_CLOSED:
        break

    if event == 'Start':
        for k,value in values.items():
            if value == True:
                window[radio_choices[k]].update(visible=True)
            else : 
                window[radio_choices[k]].update(visible=False)
window.close()