表格中的右上角单元格未显示

Question

在 Stack Overflow 几个人的帮助下，我的网页几乎完美。

我有一个从数据库中提取信息的 PHP 表。但是，由于某种原因，它将右上角的单元格留空。有 3 列和大约 200 行，唯一显示空白的单元格是右上角。

如果有人可以发布更改内容的示例代码，那就太好了。我确定这很简单，我很可能只是盯着它太久了！

表格代码在底部附近：

<?php include("header.html"); ?>

<center>
<?php
    /*
        Place code to connect to your DB here.
    */
    include('database.php');    // include your code to connect to DB.

    $tbl_name="list";       //your table name
    // How many adjacent pages should be shown on each side?
    $adjacents = 3;

    /* 
       First get total number of rows in data table. 
       If you have a WHERE clause in your query, make sure you mirror it here.
    */
    $query = "SELECT COUNT(*) as num FROM $tbl_name";
    $total_pages = mysql_fetch_array(mysql_query($query));
    $total_pages = $total_pages[num];

    /* Setup vars for query. */
    $targetpage = "index.php";  //your file name  (the name of this file)
    $limit = 1001;                              //how many items to show per page
    $page = $_GET['page'];
    if($page) 
        $start = ($page - 1) * $limit;          //first item to display on this page
    else
        $start = 0;                             //if no page var is given, set start to 0

    /* Get data. */
    $sql = "SELECT website FROM $tbl_name LIMIT $start, $limit";
    $result = mysql_query($sql);

    /* Setup page vars for display. */
    if ($page == 0) $page = 1;                  //if no page var is given, default to 1.
    $prev = $page - 1;                          //previous page is page - 1
    $next = $page + 1;                          //next page is page + 1
    $lastpage = ceil($total_pages/$limit);      //lastpage is = total pages / items per page, rounded up.
    $lpm1 = $lastpage - 1;                      //last page minus 1

    /* 
        Now we apply our rules and draw the pagination object. 
        We're actually saving the code to a variable in case we want to draw it more than once.
    */
    $pagination = "";
    if($lastpage > 1)
    {   
        $pagination .= "<div class=\"pagination2\">";
        //previous button
        if ($page > 1) 
            $pagination.= "<a href=\"$targetpage?page=$prev\">&lt; previous</a>";
        else
            $pagination.= "<span class=\"disabled\">&lt; previous</span>";  

        //pages 
        if ($lastpage < 7 + ($adjacents * 2))   //not enough pages to bother breaking it up
        {   
            for ($counter = 1; $counter <= $lastpage; $counter++)
            {
                if ($counter == $page)
                    $pagination.= "<span class=\"current\">$counter</span>";
                else
                    $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";                 
            }
        }
        elseif($lastpage > 5 + ($adjacents * 2))    //enough pages to hide some
        {
            //close to beginning; only hide later pages
            if($page < 1 + ($adjacents * 2))        
            {
                for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<span class=\"current\">$counter</span>";
                    else
                        $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";                 
                }
                $pagination.= "...";
                $pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
                $pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";       
            }
            //in middle; hide some front and some back
            elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
            {
                $pagination.= "<a href=\"$targetpage?page=1\">1</a>";
                $pagination.= "<a href=\"$targetpage?page=2\">2</a>";
                $pagination.= "...";
                for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<span class=\"current\">$counter</span>";
                    else
                        $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";                 
                }
                $pagination.= "...";
                $pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
                $pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";       
            }
            //close to end; only hide early pages
            else
            {
                $pagination.= "<a href=\"$targetpage?page=1\">1</a>";
                $pagination.= "<a href=\"$targetpage?page=2\">2</a>";
                $pagination.= "...";
                for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<span class=\"current\">$counter</span>";
                    else
                        $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";                 
                }
            }
        }

        //next button
        if ($page < $counter - 1) 
            $pagination.= "<a href=\"$targetpage?page=$next\">next &gt;</a>";
        else
            $pagination.= "<span class=\"disabled\">next &gt;</span>";
        $pagination.= "</div>\n";       
    }
?>

    <?php
$i = 0;
echo '<table style="table-layout:fixed; width:1050px;"><tr>'; 
        while($row = mysql_fetch_array($result))
{
    $i ++;
    if ($i<=2)
    {
      echo '<td style="word-wrap: break-word;">
         <div><a href="http://www.test.com/check.php?site='.$row[website].'">'.$row[website].'</a></div>
       </td>'; 
    }

    else
    {       
      echo '</tr><tr>';
      echo '<td style="word-wrap: break-word;"><div><a href="http://www.test.com/check.php?site='.$row[website].'">'.$row[website].'</a></div></td>'; 
      $i = 0;
   }
}  
echo '</tr></table>';
    ?>

<?=$pagination?>
</center>

<?php include("footer.html"); ?>

Answer 1

尝试移动

$i ++;

在循环结束之前的整个条件之后：

        else
        {       
          echo '</tr><tr>';
          echo '<td style="word-wrap: break-word;"><div><a href="http://www.test.com/check.php?site='.$row[website].'">'.$row[website].'</a></div></td>'; 
          $i = 0;
       }
       $i++;

Answer 2

这个while循环的逻辑是

设置标志($test)

第一次执行 while 循环 $test = 0 和 xxxx。

循环结束

$test 设置为 1

下一次和后续时间循环yyyy被执行

$test = 0;
 echo '<table style="table-layout:fixed; width:1050px;"><tr>'; 
    while($row = mysql_fetch_array($result))
    {

    if ($test==0){
      xxxx;
    }else{
    yyyy,
    }
   $test =1;
 }