【发布时间】:2016-06-03 23:14:33
【问题描述】:
我正在尝试从 gcc auto-vectorize documentation 向量化示例 4 的简化版本。对于我的生活,我不知道该怎么做;
typedef int aint __attribute__ ((__aligned__(16)));
void foo1 (int n, aint * restrict px, aint *restrict qx) {
/* feature: support for (aligned) pointer accesses. */
int *__restrict p = __builtin_assume_aligned (px, 16);
int *__restrict q = __builtin_assume_aligned (qx, 16);
while (n--){
//*p++ += *q++; <- this is vectorized
p[n] += q[n]; // This isn't!
}
}
我正在运行 gcc 4.7.2 gcc -o 应用程序/craft_dbsplit.o -c -Wall -g -ggdb -O3 -msse2 -funsafe-math-optimizations -ffast-math -ftree-vectorize -ftree-vectorizer-verbose=5 -funsafe-loop-optimizations -std =c99
它会回复:
Analyzing loop at apps/craft_dbsplit.c:388
388: dependence distance = 0.
388: dependence distance == 0 between *D.9363_14 and *D.9363_14
388: dependence distance = 0.
388: accesses have the same alignment.
388: dependence distance modulo vf == 0 between *D.9363_14 and *D.9363_14
388: vect_model_load_cost: unaligned supported by hardware.
388: vect_get_data_access_cost: inside_cost = 2, outside_cost = 0.
388: vect_model_store_cost: unaligned supported by hardware.
388: vect_get_data_access_cost: inside_cost = 2, outside_cost = 0.
388: Alignment of access forced using peeling.
388: Vectorizing an unaligned access.
388: vect_model_load_cost: aligned.
388: vect_model_load_cost: inside_cost = 1, outside_cost = 0 .
388: vect_model_load_cost: unaligned supported by hardware.
388: vect_model_load_cost: inside_cost = 2, outside_cost = 0 .
388: vect_model_simple_cost: inside_cost = 1, outside_cost = 0 .
388: not vectorized: relevant stmt not supported: *D.9363_14 = D.9367_20;
apps/craft_dbsplit.c:382: note: vectorized 0 loops in function.
【问题讨论】:
-
"我正在运行 gcc 4.7.2" 您可能需要更新它,它已经很旧了。较新的版本确实对循环进行了矢量化。
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虽然gcc内置的vector很烂但是你可以试试
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对于它的价值:给定
while(n--),那么*p++ += *q++;不等于p[n] += q[n];。第二个版本向后迭代。
标签: c gcc auto-vectorization