替换行索引的算法

Question

一般：

我有一条短信

Sample1 Text1 Line 1
Sample2 Text2 Line 2
Sample3 Text3 Line 3

还有一个数组['LEFT', 'RIGHT', 'CENTER']，它代表了对齐方式..

假设，我删除了Line 1 Sample2，这使得文本成为：

Sample1 Text1 
Text2 Line 2
Sample3 Text3 Line 3

对齐数组应该保持不变：['LEFT', 'RIGHT', 'CENTER'] 但是，如果我删除第二行，数组应该更改为 ['LEFT','CENTER']

反之亦然...当在第 1 行和第 2 行之间添加一行时，它应该通过从“扩展”行中获取对齐来将数组更改为 ['LEFT', 'LEFT', 'RIGHT', 'CENTER']...

是的...我知道...令人困惑...

https://jsfiddle.net/redlive/yuz08axc/

Answer 1

你想要这个

let text = 'a\nb\nc\n'
const textAsArray = text.split('\n')
const alignments = ['left', 'right', 'center']

// initial
console.log('initial state:', text, alignments)

// remove second line
removeLine(1)
console.log('removed second line:', text, alignments)


// add second line
addLine(1, 'b')
console.log('added second line:', text, alignments)

function removeLine(num) {
  textAsArray.splice(num,1)
  alignments.splice(num,1)
  text = textAsArray.join('\n')
}


function addLine(num, val) {
  textAsArray.splice(num, 0, val)
  alignments.splice(num, 0, alignments[num ? num - 1 : 'left' /* left is default */ ])
  text = textAsArray.join('\n')
}