【问题标题】:Getting value from checkbox created from $.post results从 $.post 结果创建的复选框中获取价值
【发布时间】:2017-07-13 08:06:48
【问题描述】:

我有一组从 $.post 返回结果创建的复选框。每次从下拉列表中选择不同的人时,都会创建这些复选框,并为每个人显示不同的人。

$.post("api.php/atherapists", {clientID: clientID}).done(function(data){

  var data = JSON.parse(data);

  var trHTML = '';

  $.each(data, function(i, item){
      therapistID = item.therapist_id;
      therapistName = item.therapist_name;

      trHTML += '<tr><td><input type="checkbox" name="achkbox" id="achkbox" value="' + therapistID + '"></td><td>' + therapistName + '</td></tr>';
  });
  $('#tableAvailable').empty();
  $('#tableAvailable').append(trHTML);

});

我的问题是关于在单击复选框时从复选框中获取值。我计划在单击其中一个复选框并将其值发送到 php 以进行处理时,让函数从 $.post 中触发 mysqli 查询。每次我尝试提醒选中复选框的值时,都没有任何反应。这些我都试过了

$("input[name='achkbox']").change(function(){
    alert($(this).attr('value'));       
});

$('#achkbox').click(function(){
    alert($(this).attr('value'));        
});

$('#achkbox').change(function(){
    var id = $(this).val();
    if(id != null){
        alert(id);
    }
});

似乎没有返回/显示我需要发送到 php 以处理此人的值。我可以弄清楚如何即时将数据发送到 php,但我无法弄清楚我在获取值时做错了什么。

编辑 - 2017 年 2 月 23 日 我已经实现了 Fermin 的建议,这些建议很漂亮,但这是我的困境

$.post("api.php/atherapists", {clientID: clientID}).done(function(data){

    var data = JSON.parse(data);

    var table = $('#tableAvailable');
    var trHTML = '';
    $('#tableAvailable').empty();

    $.each(data, function(i, item){
        therapistID = item.therapist_id;
        therapistName = item.therapist_name;

        var tr = $('<tr></tr>');
        var td1 = $('<td></td>');
        var td2 = $('<td></td>');
        var checkbox = $('<input type="checkbox" name="achkbox" id="achkbox" value="' + therapistID + '" >').click(function(){

           var theraID = $(this).val();

           //fire ajax call to assign selected therapist to client
           $.post("api.php/assignsave", {clientID: clientID, therapist: theraID}).done(function(data){

           //after assignment refresh the table by running $.post("api.php/atherapists) again
           //maybe making this whole thing a function then recalling it after post

           });


        });

     tr.append(td1.append(checkbox)).append(td2.append(therapistName));
     table.append(tr);
   });


});

2017 年 2 月 23 日上午 9:55 编辑

使用 Fermin 解决方案和一些函数的混合物使其工作。这就是我所做的

function getATherapists(clientID){
    $.post("api.php/atherapists", {clientID: clientID}).done(function(data){

        var data = JSON.parse(data);

        var table = $('#tableAvailable');
        var trHTML = '';
        $('#tableAvailable').empty();

        $.each(data, function(i, item){
            therapistID = item.therapist_id;
            therapistName = item.therapist_name;

            var tr = $('<tr></tr>');
            var td1 = $('<td></td>');
            var td2 = $('<td></td>');
            var checkbox = $('<input type="checkbox" name="achkbox" id="achkbox" value="' + therapistID + '" >').click(function(){

            var theraID = $(this).val();

            //assign therapist to client
            $.post("api.php/assignsave", {clientID: clientID, therapist: theraID}).done(function(data){

                //call getATherapists function
                getATherapists(clientID);

                //create a new function to get current therapists since getCTherapists is further down the list  
                function getCurrentTherapists(clientID){
                    $.post("api.php/ctherapists", {clientID: clientID}).done(function(data){

                        var data = JSON.parse(data);

                        var table = $('#tableCurrent');
                        var trHTML = '';
                        $('#tableCurrent').empty();

                        $.each(data, function(i, item){
                            therapistID = item.therapist_id;
                            therapistName = item.therapist_name;

                            var tr = $('<tr></tr>');
                            var td1 = $('<td></td>');
                            var td2 = $('<td></td>');
                            var checkbox = $('<input type="checkbox" name="cchkbox" id="cchkbox" value="' + therapistID + '" >').click(function(){

                                var theraID = $(this).val();

                                //assign therapist to client
                                $.post("api.php/removesave", {clientID: clientID, therapist: theraID}).done(function(data){

                                    //rerun getCurrentTherapists & getATherapists                          
                                    getCurrentTherapists(clientID);
                                    getATherapists(clientID);
                                });
                            });

                            tr.append(td1.append(checkbox)).append(td2.append(therapistName));
                            table.append(tr);
                                    });


                                });
                                };
                                getCurrentTherapists(clientID);
                            });


                        });

                        tr.append(td1.append(checkbox)).append(td2.append(therapistName));
                        table.append(tr);
                    });


                });
                };

function getCTherapists(clientID){
                    $.post("api.php/ctherapists", {clientID: clientID}).done(function(data){

                    var data = JSON.parse(data);

                    var table = $('#tableCurrent');
                    var trHTML = '';
                    $('#tableCurrent').empty();

                    $.each(data, function(i, item){
                        therapistID = item.therapist_id;
                        therapistName = item.therapist_name;

                        var tr = $('<tr></tr>');
                        var td1 = $('<td></td>');
                        var td2 = $('<td></td>');
                        var checkbox = $('<input type="checkbox" name="cchkbox" id="cchkbox" value="' + therapistID + '" >').click(function(){

                            var theraID = $(this).val();

                            //assign therapist to client
                            $.post("api.php/removesave", {clientID: clientID, therapist: theraID}).done(function(data){

                                //refresh the available table which would run $.post("api.php/atherapists) again
                                getCTherapists(clientID);
                                getATherapists(clientID);
                            });


                        });

                        tr.append(td1.append(checkbox)).append(td2.append(therapistName));
                        table.append(tr);
                    });


                });
                };


                getATherapists(clientID);
                getCTherapists(clientID);

【问题讨论】:

标签: php jquery checkbox mysqli


【解决方案1】:

http://jsfiddle.net/

$(document).ready(function() {
  var data = [
		{therapist_id: 'id1', therapist_name: 'nam1'},
    {therapist_id: 'id2', therapist_name: 'nam2'},
    {therapist_id: 'id3', therapist_name: 'nam4'},
];
var table = $('#tableAvailable');
 var trHTML = '';
  $.each(data, function(i, item){
      therapistID = item.therapist_id;
      therapistName = item.therapist_name;
      var tr = $('<tr></tr>');
      var td1 = $('<td></td>');
      var td2 = $('<td></td>');
			var checkbox = $('<input type="checkbox" name="achkbox" id="achkbox" value="' + therapistID + '">').click(function(){
      	console.log( $( this ).val() );
        alert($( this ).val());
      });
      tr.append(td1.append(checkbox)).append(td2.append(therapistName));
      table.append(tr);
  });
  
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<table id="tableAvailable" >
 
 </table>

o2gxgz9r/3154/#&togetherjs=JtIhtUULoM

试试这样的

    var renderTable = function renderTable(data){
    var data = JSON.parse(data);

        var table = $('#tableAvailable');
        var trHTML = '';
        table.empty();

        $.each(data, function(i, item){
            therapistID = item.therapist_id;
            therapistName = item.therapist_name;

            var tr = $('<tr></tr>');
            var td1 = $('<td></td>');
            var td2 = $('<td></td>');
            var checkbox = $('<input type="checkbox" name="achkbox" id="achkbox" value="' + therapistID + '" >').click(function(){

               var theraID = $(this).val();

               //fire ajax call to assign selected therapist to client
               $.post("api.php/assignsave", {clientID: clientID, therapist: theraID}).done(function(data){

               //after assignment refresh the table by running $.post("api.php/atherapists) again
               //maybe making this whole thing a function then recalling it after post
                renderTable(data);
               });


            });

         tr.append(td1.append(checkbox)).append(td2.append(therapistName));
         table.append(tr);
       });

};

$.post("api.php/atherapists", {clientID: clientID}).done(function(data){
        renderTable(data);
    });

【讨论】:

  • 这很好,但我觉得它提出了一个无限循环问题,因为我想将 ID 发布到数据库并刷新表。在复选框单击事件期间,我会将 ID $.post 到 php 并在完成功能中,id 希望表格刷新以显示更改。
  • 你可以在点击函数 var checkbox = $('' ).click(function(){ console.log( $( this ).val() ); alert($( this ).val()); });
  • 我得到了它的工作...检查编辑。混合使用了您的建议和功能
猜你喜欢
  • 1970-01-01
  • 2013-03-21
  • 2018-07-24
  • 1970-01-01
  • 1970-01-01
  • 2015-08-15
  • 1970-01-01
  • 1970-01-01
  • 2017-10-02
相关资源
最近更新 更多