【发布时间】:2015-06-18 16:40:54
【问题描述】:
我必须向学生展示复选框,如果有明确的老师教这些学生,他们必须被检查。如果这些学生不是他的学生,那就不用查了。我有两个查询来计算 2 个值,但在我的情况下,当它们相等时,不会在 ckechboxes 中检查学生,而是写成:checked="checked" > >。以及如何关闭我的复选框,在学生姓名前显示> > >。
我的看法是:
<?php
foreach($select_students as $student)
{
?>
<tr><td class='col-md-2'>
<input type="checkbox" name="student[]" value="<?php echo $student->user_id; ?>"
<?php foreach($select_teachers_students as $select) {
echo $student->user_id == $select->student_id ? 'checked="checked"' : ''
; ?> >
<?php }
echo $student->username; ?>
</td><td>
我的模型是:
public function select_students() {
$this->db->select('users.user_id, users.username, users.school_id, users.class, users.division, users.role_id, schools.school_name, schools.region,class_divisions.division');
$this->db->from('users');
$this->db->join('class_divisions','class_divisions.id=users.division','left');
$this->db->join('schools','schools.school_id=users.school_id','left');
$this->db->where('(users.deactivated_at = "0000-00-00 00:00:00" OR users.deactivated_at IS NULL) AND users.role_id = 1 ');
$this->db->where('users.school_id',$this->uri->segment(4) );
$result=$this->db->get();
return $result->result();
}
public function edit_students() {
$submit=$this->input->post('change');
$date = new DateTime("now");
if(isset($submit)&&($submit=='Промени ученици')) {
if($this->input->post('student')) {
foreach($this->input->post('student') AS $student) {
$data = array(
'student_id' => $student,
// 'teacher_id' => $this->uri->segment(3),
'created_at' => $date->format('Y-m-d H:i:s')
);
$this->db->where('teacher_id',$this->uri->segment(3));
$this->db->update('teacher_student_conn', $data);
if($this->db->affected_rows() > 0)
{
return true;
}
return false;
}
}
}
}
我的控制器是:
public function edit_students()
{
if($this->admin_model->edit_students()) {
echo "Tou changed teacher successfully!";
$teacher_id = $this->uri->segment(3);
$school_id = $this->uri->segment(4);
header('Refresh: 2; url=/survey/index.php/admin/edit_students/'.$teacher_id .'/' .$school_id);
}
else
{
$data['dynamic_view'] = 'edit_students';
$data['select_students']=$this->admin_model->select_students();
$data['select_teachers_students']=$this->admin_model->select_teachers_students();
$data['teacher_name']=$this->admin_model->teacher_name();
$data['menu']=$this->menu_model->get_menu();
$this->load->view('templates/main',$data);
}
}
public function select_teachers_students() {
$this->db->select('*');
$this->db->from('teacher_student_conn');
$this->db->where('teacher_student_conn.teacher_id',$this->uri->segment(3) );
$result=$this->db->get();
return $result->result();
}
public function edit_students() {
$submit=$this->input->post('change');
$date = new DateTime("now");
if(isset($submit)&&($submit=='Промени ученици')) {
if($this->input->post('student')) {
foreach($this->input->post('student') AS $student) {
if($this->input->post('student')==$this->select_teachers_students()) {
$data = array(
'student_id' => $student,
'created_at' => $date->format('Y-m-d H:i:s')
);
$this->db->where('teacher_id',$this->uri->segment(3));
$this->db->update('teacher_student_conn', $data);
}
else if($this->input->post('student')!=$this->select_teachers_students()) {
$data = array(
'student_id' => $student,
'teacher_id' => $this->uri->segment(3),
'created_at' => $date->format('Y-m-d H:i:s')
);
$this->db->insert('teacher_student_conn', $data);
}
}
if($this->db->affected_rows() > 0)
{
return true;
}
return false;
}
}
}
但插入我已经拥有的行。我尝试使用函数 select_teachers_students() 进行检查,如果它们在那里,我不想再次插入 - 我想更新它们。以及如何在选中复选框时设置复选框的值,插入value="<?php echo $student->user_id; ?>" 但是,当未选中复选框并且我按下提交按钮时,插入Value='0'。如果它们不存在,我想插入。
【问题讨论】:
-
我改变了展示方式。这种方式更复杂。 :)
标签: php codeigniter if-statement checkbox checked