句点、单词和冒号的正则表达式答案

【问题标题】：Regex for period, word, and then colon句点、单词和冒号的正则表达式
【发布时间】：2021-05-07 09:36:28
【问题描述】：

是否有正则表达式、python 或 javascript 方法来搜索句点、单词和定义，然后将其附加到字典或其他对象？

例如：

。回归：回归是再次回到以前的状态或条件。修辞：修辞是使用语言说服或影响人们的技能或艺术，尤其是听起来令人印象深刻但可能不真诚或不诚实的语言。

这将变成{"Reversion" : "A reversion is turning back again to a previous state or condition", "Rhetoric" : "Rhetoric is the skill or art of using language to persuade or influence people, especially language that sounds impressive but may not be sincere or honest" }

【问题讨论】：

/\. (.*): (.*)\./ 这应该可以工作
我不会为此使用正则表达式，这是一个相当复杂的表达式。请记住：“有些人在遇到问题时会想“我知道，我会使用正则表达式。”现在他们有两个问题。”

标签： javascript python regex

【解决方案1】：

我在原句中插入了几句，以表明该方案可以获取文本中任意位置的模式。

我使用 reduce 将 matchAll 的返回值转换为一个对象。

x = `asoidn aiosjdn yaosui noapids poasm daioansoid apaoms d. Reversion: A reversion is turning back again to a previous state or condition. aasd aeoinad oianfds inauireb docn isenm opisd a. Rhetoric: Rhetoric is the skill or art of using language to persuade or influence people, especially language that sounds impressive but may not be sincere or honest.`;

matches = [...x.matchAll(/(\w+)\s*:\s*([^.:]+.)/g)];

obj = matches.reduce((dict, [_, name, text]) => (dict[name] = text, dict), {});

console.log(obj);

【讨论】：

【解决方案2】：

看看这段代码：

my_final_result = {}
input_str = ". Reversion: A reversion is turning back again to a previous state or condition. Rhetoric: Rhetoric is the skill or art of using language to persuade or influence people, especially language that sounds impressive but may not be sincere or honest."
# assuming that periods don't occur in definitions and only separate the particular definition from another
input_list = input_str.split(".")
for definition in input_list:
    definition_list = definition.split(":")
    if len(definition_list) == 2:  # check if definition is correct
        # save our key-value pair to dictionary. strip() deletes some possible spaces around the words
        my_final_result[definition_list[0].strip()] = definition_list[1].strip()
print(my_final_result)

【讨论】：

【解决方案3】：

过滤掉单词的正则表达式和定义是：

\.\s*([^:]*)\s*:\s*([^.]*)

演示：https://regex101.com/r/utgrCb/1/

\.\s* 起始点和可选空格
([^:]*)“单词”是冒号之前的所有内容
\s*:\s*冒号用可选空格包围
([^.]*)“定义”是最后一个点之前的所有内容

【讨论】：

【解决方案4】：

我想使用reduce，但最终得到了这个

const str = `Reversion: A reversion is turning back again to a previous state or condition. Rhetoric: Rhetoric is the skill or art of using language to persuade or influence people, especially language that sounds impressive but may not be sincere or honest.`

const dict = {}
const arr = str.split(/[$\.]?(\w+): /g).slice(1)
for (let i=0;i<arr.length-1;i+=2) {
  dict[arr[i]] = arr[i+1].trim()
}
console.log("dict",dict)

【讨论】：