我正在尝试从终端构建 IPA。我尝试了以下步骤： 第 1 步：
/usr/bin/xcodebuild -target "appname" -sdk "iphoneos" -configuration Release
第 2 步：
/usr/bin/xcrun -sdk iphoneos PackageApplication -v "appname" -o "/Users/Pictures/" -sign "iPhone Developer:xxxxx" --embed /Users//Library/MobileDevice/Provisioning\ Profiles/xxxxxx.mobileprovision"
我没有收到任何错误，但没有收到任何回复。我已经等了30多分钟了。我在这里错过了什么？
【问题讨论】：
I have given a brief description of steps to follow, and parameters to pass while generating an ipa using terrminal below:
1) Go to the folder which contains the MyApp.xcodeproject file in terminal
2) By using the command given below you will get all the Targets of the application
/usr/bin/xcodebuild -list
3) After the above command is executed, you will get a list of targets of which you should select a specific target you need to generate .ipa
/usr/bin/xcodebuild -target $TARGET -sdk iphoneos -configuration Release
4) The above command builds the project and creates a .app file.The path to locate the .app file is"./build/Release-iphoneos/MyApp.app"
5) After Build gets succeeded then execute the following command to generate .ipa of the application using Developer Name and Provisioning Profile using the syntax below:
/usr/bin/xcrun -sdk iphoneos PackageApplication -v “${TARGET}.app” -o “${OUTDIR}/${TARGET}.ipa” –sign “${IDENTITY}” –embed “${PROVISONING_PROFILE}”
Explanation of each Parameter in the above syntax:
${TARGET}.app == Target path (ex :/Users/XXXXXX/desktop/Application/build/Release-iphoneos/MyApp.app) ${OUTDIR} == Select the output directory(Where you want to save .ipa file) ${IDENTITY} == iPhone Developer: XXXXXXX (XXXXXXXXXX)(which can be obtained from Keychain access) ${PROVISONING_PROFILE} == Path to the provisioning profile(/Users/XXXXXX/Library/MobileDevice/Provisioning Profiles/XXXXXXXX-XXXX-XXXX-XXXX-XXXXXXXXXXXX.mobileprovision”)
6)ipa will be generated at selected output directory "${OUTDIR}"
【讨论】：