【问题标题】:Pagination with Flask and Peewee使用 Flask 和 Peewee 进行分页
【发布时间】:2016-04-14 13:28:07
【问题描述】:

我正在尝试使用PeeweeFlask 中的查询结果进行paginate。我正在尝试使用来自playhouse.flask_utils 的函数object_list

你可以看到object_list 的例子看起来很简单,下面的代码是我想要做的:

from flask import Flask
from playhouse.flask_utils import object_list
from peewee import *
from database import *

@app.route("/items/")                                                         
def items():                                                                  
    all_items = Quote.select()                                                     
    return object_list("items.html", all_items) 

模板items.html 包含以下内容:

<p>Hello world</p>                                               
{% for item in all_items %}                                                       
    <p>{{ item.text }}</p>                                                    
{% endfor %}                                                                    

{% if page > 1 %}                                                               
    <a class="previous" href="./?page={{ page - 1 }}">Previous</a>              
{% endif %}                                                                     
{% if pagination.get_pages() > page %}                                          
    <a class="next" href="./?page={{ page + 1 }}">Next</a>                      
{% endif %}        

当然,我运行python app.py,但收到500 内部服务器错误。我有兴趣对查询结果进行分页,知道如何实现吗?或者你能发现我在这里做错了什么吗?先感谢您。

编辑#1,终端出现如下错误:

127.0.0.1 - - [09/Jan/2016 20:47:17] "GET /items/ HTTP/1.1" 500 -
Traceback (most recent call last):
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1836, in __call__
    return self.wsgi_app(environ, start_response)
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1820, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1403, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1817, in wsgi_app
    response = self.full_dispatch_request()
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1477, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1381, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1475, in full_dispatch_request
    rv = self.dispatch_request()
  File "/usr/lib/python2.7/site-packages/flask/app.py", line 1461, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/home/web/index.py", line 19, in items
    return object_list("items.html", all_items)
  File "/usr/lib/python2.7/site-packages/playhouse/flask_utils.py", line 64, in object_list
    **kwargs)
  File "/usr/lib/python2.7/site-packages/flask/templating.py", line 128, in render_template
    context, ctx.app)
  File "/usr/lib/python2.7/site-packages/flask/templating.py", line 110, in _render
    rv = template.render(context)
  File "/usr/lib/python2.7/site-packages/jinja2/environment.py", line 989, in render
    return self.environment.handle_exception(exc_info, True)
  File "/usr/lib/python2.7/site-packages/jinja2/environment.py", line 754, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/home/web/templates/items.html", line 9, in top-level template code
    {% if pagination.get_pages() > page %}
UndefinedError: 'playhouse.flask_utils.PaginatedQuery object' has no attribute 'get_pages'

【问题讨论】:

  • 你的错误信息是什么?
  • @EliRose 感谢您的关注。我编辑了我的问题并添加了出现在终端中的错误消息!
  • Python 回溯会更有帮助——当您访问该页面时,它应该会显示在您的浏览器中。有这种情况吗?
  • @EliRose 不,它没有发生。没有出现回溯。
  • 调试是否开启?如果是,您应该得到类似于屏幕flask.pocoo.org/docs/0.10/quickstart 的东西。如果不是,请打开它。

标签: python flask pagination peewee flask-peewee


【解决方案1】:

没有get_pages() 方法。使用:get_page(x) 获取结果页面。使用get_page_count()获取总页数。

这都记录在这里:http://docs.peewee-orm.com/en/latest/peewee/playhouse.html#PaginatedQuery

【讨论】:

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