【发布时间】：2020-09-03 12:30:20
【问题描述】：
我正在尝试使用 JSON 文件中的节点 js 创建 API。
我从 JSON 文件创建了一个来自 Nodejs 的简单获取请求，我试图从 json 文件中删除不需要的数据并从该 json 文件构造新的响应
我的代码如下：
var express = require("express");
const bodyParser = require('body-parser');
var app = express();
app.use(function(req, res, next) {
res.header("Access-Control-Allow-Origin", "*");
res.header("Access-Control-Allow-Headers", "Origin, X-Requested-With, Content-Type, Accept");
next();
});
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({ extended: true }));
const fs = require('fs');
const Test_Data = './data/testData.json';
app.get('/all', (req, res) => {
fs.readFile(Test_Data, 'utf8', (err, data) => {
if (err) {
throw err;
}
res.send(JSON.parse(data));
});
});
// finally, launch our server on port 3001.
const server = app.listen(3000, () => {
console.log('listening on port %s...', server.address().port);
});
我的testData.json如下
[
{
"web-scraper-order": "1588668196-10",
"web-scraper-start-url": "https://udemycoupon.learnviral.com/coupon-category/development/page/266",
"pagenation": "",
"pagenation-href": "",
"courseid": "Redeem Offer",
"courseidhref": "https://www.udemy.com/course/amazon-alexa-101-publishing-alexa-skills-without-coding/"
},
{
"web-scraper-order": "1588668196-12",
"web-scraper-start-url": "https://udemycoupon.learnviral.com/coupon-category/development/page/266",
"pagenation": "",
"pagenation-href": "",
"courseid": "Redeem Offer",
"courseidhref": "https://www.udemy.com/course/learn-complete-oracle-apps-r12-technical-training/?couponCode=TTROAP"
}
]
在这个 testData.json 文件中我得到了不需要的数据
我正在尝试如下创建 JSON 响应
[
{
"id": "1",
"courseTitle": "amazon alexa 101 publishing alexa skills without coding",
"courseidhref": "https://www.udemy.com/course/amazon-alexa-101-publishing-alexa-skills-without-coding/"
},
{
"id": "2",
"courseTitle": "learn complete oracle apps r12 technical training",
"courseidhref": "https://www.udemy.com/course/learn-complete-oracle-apps-r12-technical-training/?couponCode=TTROAP"
}
]
我正在尝试从 courseidhref
创建 courseTitle我已经完成了单独的代码
var url = require('url');
var adr ='https://www.udemy.com/course/technology-strategy-success/?couponCode=05DISC2020';
var q = url.parse(adr, true);
var data = q.pathname.replace("/course/", '');
var output = data.replace("/", '');
console.log(output);
如何结合这两个代码从 JSON 文件构造一个 json 响应？
【问题讨论】：
标签： node.js json angular api express