配置 Spring Security 以使用自定义 UsernamePasswordAuthenticationFilter

Question

我已经实现了自己的LowerCaseUsernamePasswordAuthenticationFilter，它只是UsernamePasswordAuthenticationFilter 的子类。

但现在我的问题是，如何配置 Spring 安全性以使用此过滤器。

到现在我用过：

<security:http auto-config="true" use-expressions="true">
    <security:form-login login-processing-url="/resources/j_spring_security_check" login-page="/login" authentication-failure-url="/login?login_error=t" />
    <security:logout logout-url="/resources/j_spring_security_logout" />

    <security:intercept-url pattern="/**" access="isAuthenticated()" requires-channel="${cfma.security.channel}" />
</security:http>

我真的要关闭auto-config 并需要手动配置所有过滤器吗？ - 如果这是真的，有人可以提供一个例子吗？

---

简单的添加security:custom-filter的方法：

<security:http ...>

   <security:form-login login-processing-url="/resources/j_spring_security_check" login-page="/login" authentication-failure-url="/login?login_error=t" />
   <security:custom-filter ref="lowerCaseUsernamePasswordAuthenticationFilter" position="FORM_LOGIN_FILTER"/>
   ...
 </security:http>

确实会导致该消息出现异常：

配置问题：过滤bean<lowerCaseUsernamePasswordAuthenticationFilter>和'Root bean: class [org.springframework.security.web.authentication.UsernamePasswordAuthenticationFilter];范围=;摘要=假；懒惰初始化=假；自动线模式=0；依赖检查=0；自动接线候选=真；主要=假；工厂BeanName=空；工厂方法名=空；初始化方法名=空； destroyMethodName=null' 具有相同的 'order' 值。 使用自定义过滤器时，请确保位置不与默认过滤器冲突。或者您可以通过删除相应的子元素并避免使用来禁用默认过滤器。

Answer 1

我是通过手动编写所需的自动配置 bean 来完成的。结果如下：

<!-- HTTP security configurations -->
<security:http auto-config="false" use-expressions="true" entry-point-ref="loginUrlAuthenticationEntryPoint">

    <!--
    <security:form-login login-processing-url="/resources/j_spring_security_check" login-page="/login" authentication-failure-url="/login?login_error=t" />
        replaced by lowerCaseUsernamePasswordAuthenticationFilter
        the custom-filter with position FORM_LOGIN_FILTER requries that auto-config is false!
     -->
    <security:custom-filter ref="lowerCaseUsernamePasswordAuthenticationFilter" position="FORM_LOGIN_FILTER"/>
    <security:logout logout-url="/resources/j_spring_security_logout" />

    <security:intercept-url pattern="/**" access="isAuthenticated()" />
</security:http>

<bean id="loginUrlAuthenticationEntryPoint" class="org.springframework.security.web.authentication.LoginUrlAuthenticationEntryPoint">
    <property name="loginFormUrl" value="/login"/>
</bean>

<bean id="lowerCaseUsernamePasswordAuthenticationFilter"
    class="com.queomedia.cfma.infrastructure.security.LowerCaseUsernamePasswordAuthenticationFilter">
    <property name="filterProcessesUrl" value="/resources/j_spring_security_check"/>
    <property name="authenticationManager" ref="authenticationManager"/>
    <property name="authenticationFailureHandler">
        <bean class="org.springframework.security.web.authentication.SimpleUrlAuthenticationFailureHandler">
            <property name="defaultFailureUrl" value="/login?login_error=t"/>       
        </bean>
    </property>
</bean>

Answer 2

这是 Scala 中的一个示例。我必须这样做才能替换 Spring Security OAuth 提供的过滤器。

基本上这个想法是，将FilterChainProxy 和要替换的现有过滤器注入过滤器。在filterChainMap 中找到现有的过滤器并将其替换为您的。

import org.springframework.security.oauth2.provider.verification.{VerificationCodeFilter => SpringVerificationCodeFilter}

@Component
class VerificationCodeFilter extends SpringVerificationCodeFilter with InitializingBean {
  @Autowired var filterChainProxy: FilterChainProxy = _
  @Autowired var springVerificationCodeFilter: SpringVerificationCodeFilter = _


  override def afterPropertiesSet() {
    super.afterPropertiesSet()

    val filterChainMap = filterChainProxy.getFilterChainMap
    val filterChain = 
       filterChainMap.find(_._2.exists(_.isInstanceOf[SpringVerificationCodeFilter])).
          getOrElse(throw new Exception("Could not find VerificationCodeFilter in FilterChainMap"))._2
    val index = filterChain.indexOf(springVerificationCodeFilter)
    filterChain.remove(index)
    filterChain.add(index, this)
  }
}