【发布时间】:2021-04-30 03:00:18
【问题描述】:
如何传递过滤器值来更改列表视图标题?我有报告的管理页面,我想在标题中存储日期,所以它看起来像这样:“2021 年 1 月 24 日的报告摘要” 我想从列表过滤器中获取日期报告__report_date
class AdminReportsProxy(admin.ModelAdmin):
"""Admin model, that creats site of reports summary"""
model = ReportsProxy
actions = None
search_fields = [
"first_name",
"last_name",
]
list_display = [
"get_salesman",
"get_number_of_meetings_today",
"get_number_of_meetings_tomorrow",
"get_number_of_sales",
"get_number_of_recommandations",
"get_net_sales",
"get_report_date",
"edit_report",
]
list_filter = [
("reports__report_date", DateRangeFilter),
NetSalesOrder,
]
def changelist_view(self, request, extra_context=None):
extra_context = {'title': f'Reports summary for day:{}'}
return super(AdminReportsProxy, self).changelist_view(request, extra_context=extra_context)
【问题讨论】:
标签: django filter view django-admin