【发布时间】:2021-04-07 22:26:51
【问题描述】:
我们来了!
大家好, 我正在尝试编写一个循环,其中: 如果特定列中单元格的值为“无”,并且下一个单元格的值等于国家/地区数组,那么我将“无”值更改为下一个单元格的值,即国家。
我想我在解决这个问题上有点偏离。
country_with_province = array(['Australia', 'China', 'France'], dtype=object)
for m in country_with_province:
if df5.loc[(df5['Province/State'] == None) and (df5['Country/Region'] == m):
df5.loc[:, "Province"] = df5.Province.fillna(m)
输入:
| Date | Province/State | Country/Region | Recovered | Province | |
|---|---|---|---|---|---|
| 0 | 22/01/2020 | None | Afghanistan | 0 | None |
| 1 | 22/01/2020 | None | Albania | 0 | None |
| 2 | 22/01/2020 | Tasmania | Australia | 0 | Tasmania |
| 3 | 22/01/2020 | None | Australia | 0 | None |
| 4 | 22/01/2020 | Hennan | China | 0 | Hennan |
| 5 | 22/01/2020 | Gansu | China | 0 | Gansu |
| 6 | 22/01/2020 | None | China | 0 | None |
| 7 | 22/01/2020 | Guineal French | France | 0 | Guineal French |
| 8 | 22/01/2020 | None | France | 0 | None |
输出:
| Date | Province/State | Country/Region | Recovered | Province | |
|---|---|---|---|---|---|
| 0 | 22/01/2020 | None | Afghanistan | 0 | None |
| 1 | 22/01/2020 | None | Albania | 0 | None |
| 2 | 22/01/2020 | Tasmania | Australia | 0 | Tasmania |
| 3 | 22/01/2020 | None | Australia | 0 | Australia |
| 4 | 22/01/2020 | Hennan | China | 0 | Hennan |
| 5 | 22/01/2020 | Gansu | China | 0 | Gansu |
| 6 | 22/01/2020 | None | China | 0 | China |
| 7 | 22/01/2020 | Guineal French | France | 0 | Guineal French |
| 8 | 22/01/2020 | None | France | 0 | France |
我正在处理一个有 87552 行的 df。
各位,希望你们能帮帮我!我尝试在堆栈上搜索,但失败了!
【问题讨论】:
标签: python pandas dataframe nonetype