过滤数组并返回包含对象内数组内最近字符串的对象，在另一个数组内

Question

我想返回包含对象内数组内最近字符串的对象，在另一个数组内， 我的indexOf() 只返回确切的字符串为真。

我尝试将indexOf() 替换为march()、matches()、includes() 没有任何效果。

请指教

let SellerList = [
  { supplyList: ["apple", "orange", "red apple"] },
  { supplyList: ["apple juice", "drink", "green apple", "dream app"] },
  { supplyList: ["lamp", "dog", "cat", "man"] }
];

let stringToMatch = "app";

let filteredList = SellerList.filter(
  (txt) => txt.supplyList.indexOf(stringToMatch) !== -1
);

我希望的输出是包含最近字符串的所有对象，例如：

[
  { supplyList: ["apple", "orange", "red apple"] },
  { supplyList: ["apple juice", "drink", "green apple", "dream app"] }
];

Answer 1

您在一个对象内有一个数组，在另一个数组内，因此您想定位该内部数组并在其上调用过滤器：

let SellerList = [{
  supplyList: ['apple', 'orange', 'red apple']
}];

let stringToMatch = 'app';

let filteredList = SellerList[0].supplyList.filter(txt => txt.indexOf(stringToMatch) !== -1);

console.log(filteredList)

Answer 2

请尝试以下解决方案

let SellerList = [
  { supplyList: ["apple", "orange", "red apple"] },
  { supplyList: ["apple juice", "drink", "green apple", "dream app"] },
  { supplyList: ["lamp", "dog", "cat", "man"] },
];

let stringToMatch = "app";

let filteredList = SellerList.reduce((previousValue, currentValue) => {
  if (currentValue.supplyList.join().includes(stringToMatch)) {
    previousValue = [...previousValue, { supplyList: currentValue.supplyList }];
  }

  return previousValue;
}, []);

console.log(filteredList);

见

• Array.prototype.reduce()
• Array.prototype.join()

Answer 3

您应该尝试匹配 supplyLists 的内部字符串而不是数组本身。

let SellerList = [ 
                     { supplyList: ['apple','orange','red apple'] },
                     { supplyList: ['apple juice','drink','green apple'] } 
                   ];
  
  let stringToMatch = 'app';

  let filteredList = SellerList.map(list => {
    
    return list.supplyList.filter(item => {
      return item.indexOf(stringToMatch) >= 0
    })
  
  });
  
  
  console.log(filteredList);