如何根据日期属性之间的范围是否包括给定日期来过滤对象数组？答案

【问题标题】：How to filter an array of objects based on whether the range between their date properties includes a given date?如何根据日期属性之间的范围是否包括给定日期来过滤对象数组？
【发布时间】：2020-11-15 00:08:12
【问题描述】：

如何根据日期范围是否包含特定日期来过滤它们？

let visitors = [{
  "S.NO": 1,
  "Full Name": "Boss",
  "Check In": "2020-04-21 01:51:49",
  "Check Out": ""
}, {
  "S.NO": 2,
  "Full Name": "John",
  "Check In": "2020-04-19 11:21:17",
  "Check Out": "2020-04-19 12:21:26"
}, {
  "S.NO": 3,
  "Full Name": "Doll",
  "Check In": "2020-04-02 11:19:48",
  "Check Out": "2020-04-02 15:19:58"
}];

我想按以下日期过滤以上数据：

let knowntime = "2020-04-02 13:20:22";

这是我正在寻找的结果：

let filtered = [{
  "S.NO": 3,
  "Full Name": "Doll",
  "Check In": "2020-04-02 11:19:48",
  "Check Out": "2020-04-02 15:19:58"
}];

我该怎么做？

【问题讨论】：

标签： javascript json sorting date filter

【解决方案1】：

let visitors = [{
  "S.NO": 1,
  "Full Name": "Boss",
  "Check In": "2020-04-21 01:51:49",
  "Check Out": ""
}, {
  "S.NO": 2,
  "Full Name": "John",
  "Check In": "2020-04-19 11:21:17",
  "Check Out": "2020-04-19 12:21:26"
}, {
  "S.NO": 3,
  "Full Name": "Doll",
  "Check In": "2020-04-02 11:19:48",
  "Check Out": "2020-04-02 15:19:58"
}];

let knowntime = "2020-04-02 13:20:22";

let filtered = visitors.filter(visitor => {
  return visitor['Check In'] < knowntime && visitor['Check Out'] > knowntime;
});

console.log(filtered);

你也可以像这样写一个单行：

let filtered = visitors.filter(({ ['Check In']: a, ['Check Out']: b }) => a < knowntime && b > knowntime);

【讨论】：

【解决方案2】：

要过滤访问者数据，首先确保两个属性中都有值，然后使用new Date() 将值转换为日期格式，然后进行比较。

   let visitors = [
      {
        "S.NO": 1,
        "Full Name": "Boss",
        "Check In": "2020-04-21 01:51:49",
        "Check Out": ""
      },
      {
        "S.NO": 2,
        "Full Name": "John",
        "Check In": "2020-04-19 11:21:17",
        "Check Out": "2020-04-19 12:21:26"
      },
      {
        "S.NO": 3,
        "Full Name": "Doll",
        "Check In": "2020-04-02 11:19:48",
        "Check Out": "2020-04-02 15:19:58"
      }
    ];
    let knowntime = "2020-04-02 13:20:22";

    let filteredVisitors =  visitors.filter((visitor) => {
      return (visitor['Check In'] && visitor['Check Out'] &&
        (new Date(visitor['Check In']) <= new Date(knowntime) && new Date(visitor['Check Out']) >= new Date(knowntime)))
    })

    console.log(filteredVisitors)

【讨论】：

【解决方案3】：

let visitors=[ { "S.NO": 1, "Full Name": "Boss", "Check In": "2020-04-21 01:51:49", "Check Out": "" }, { "S.NO": 2, "Full Name": "John", "Check In": "2020-04-19 11:21:17", "Check Out": "2020-04-19 12:21:26" }, { "S.NO": 3, "Full Name": "Doll", "Check In": "2020-04-02 11:19:48", "Check Out": "2020-04-02 15:19:58" } ];
let knowntime="2020-04-02 13:20:22";
res=visitors.filter(o => o["Check In"].localeCompare(knowntime) < 0 && o["Check Out"].localeCompare(knowntime)>0)
console.log(res)

【讨论】：

【解决方案4】：

let visitors=[
  {
    "S.NO": 1,
    "Full Name": "Boss",
    "Check In": "2020-04-21 01:51:49",
    "Check Out": ""
  },
  {
    "S.NO": 2,
    "Full Name": "John",
    "Check In": "2020-04-19 11:21:17",
    "Check Out": "2020-04-19 12:21:26"
  },
  {
    "S.NO": 3,
    "Full Name": "Doll",
    "Check In": "2020-04-02 11:19:48",
    "Check Out": "2020-04-02 15:19:58"
  }
];
let knowntime="2020-04-02 13:20:22";
const dateToBeFiltered=new Date(knowntime);
const filterdVisitors= visitors.filter((elem)=>{

const checinTime=new Date(elem["Check In"]);
const checkOutTime=new Date(elem["Check Out"]);
return (checinTime<=dateToBeFiltered && dateToBeFiltered<=checkOutTime);

});
console.log(filterdVisitors);

【讨论】：

【解决方案5】：

从数据中可以清楚地看出，退房时间可能存在空值。如果 Check Out 为空，您是否应该认为 Check Out 大于给定时间。

这是代码

   let visitors = [
  {
    "S.NO": 1,
    "Full Name": "Boss",
    "Check In": "2020-04-21 01:51:49",
    "Check Out": ""
  },
  {
    "S.NO": 2,
    "Full Name": "John",
    "Check In": "2020-04-19 11:21:17",
    "Check Out": "2020-04-19 12:21:26"
  },
  {
    "S.NO": 3,
    "Full Name": "Doll",
    "Check In": "2020-04-02 11:19:48",
    "Check Out": "2020-04-02 15:19:58"
  }
];
let knowntime = "2020-04-02 13:20:22";

let filteredVisitors =  visitors.filter((visitor) => {
  return (new Date(visitor['Check In']) <= new Date(knowntime) && (visitor['Check Out'] === '' || new Date(visitor['Check Out']) >= new Date(knowntime)))
})

console.log(filteredVisitors)

【讨论】：