如何根据多个条件从 ArrayList 中获取元素？

Question

我正在创建一个界面来管理不同周/剧院的电影票预订。

我有一个电影课：

public class Film {

  private String title;
  private Double price;
  private String ageRestriction;
  private double rating;
  private String genre;
  private String location;
  private String screenDay;
}

一个 FilmList 类，用于在 ArrayList 中创建和存储所有电影：

public class FilmList {

  private ArrayList <Film> filmArrayList;

  public FilmList (){
    this.filmArrayList = new ArrayList<>();
  }

  public void addFilm(Film films){
    this.filmArrayList.add(films);
  }

这是图形单元界面。我要做的是根据两个条件在 ArrayList 中捕获 一个元素： 从用户中选择的周和剧院，还添加了一种检查所选参数列表中是否只有一个元素的方法。这很重要，因为每个电影实例都将被调用并在 FXML 文件的标签上“设置”（并且因为我正在考虑实现一个接口以在 ArrayList 中添加电影）。

谢谢大家。

Answer 1

好的，所以在您的示例中，它将类似于以下内容：

   //try to find any movie that suits two predicates, 1st - that it's price is greater than 30( this is random number, you can put a value from your textfield here ) and 2nd - that it's title contains Spiderman ( again, put a value from your textfield title search here for your need )
   Optional<Film> movie = listOfMovies.stream().filter(i -> i.getPrice() > 30 && i.getTitle.contains("Spiderman")).findAny();
  // if any movie has been found to suits provided criterias
   if(movie.isPresent())
       {
               //print it on screen, note method get()
               //again this is just for example here, in your code,
               // you can do with this result whatever you like
               // for example show all data about that movie on screen    
               System.out.println("---->" +movie.get());
       }
      else
       {
              // if not found do nothing
              System.out.println("Nothing found...");
       }

More about Optional can be found here.