Webflux - 多次读取单声道（请求）

Question

首先，我很困惑使用反应式处理程序方法参数是否有任何好处。 其次，当我需要多次读取这些参数时，我在使用这种技术时遇到了一些问题。

public Mono<TokenDto> generateToken(Mono<UserDto> user) {
        var userDto = user.block();
        return userRepository.findByEmail(userDto.getEmail())
                .filter(foundUser -> bCryptPasswordEncoder.matches(userDto.getPassword(), foundUser.getPassword()))
                .map(foundUser -> JWT.create()
                        .withSubject(foundUser.getEmail())
                        .withExpiresAt(new Date(System.currentTimeMillis() + jwtTtl.toMillis()))
                        .withClaim(USER_ROLES_CLAIM, foundUser.getRoles().stream().map(RoleEnum::name).collect(Collectors.toList()))
                        .sign(Algorithm.HMAC512(jwtSecret))
                )
                .map(TokenDto::new);
    }

如您所见，我需要阻止两次实际读取参数。我尝试 zipWith userRepository 结果，但最终在 Tuple2 结构中使用 Mono。

Reactor 对此有任何解决方案吗？也许有一个功能发布/重复可以通过承诺。我已经设法建立了一个管道，但是在多次读取请求正文时总是出错。

谢谢。

错误：

"timestamp": "2020-07-03T06:24:23.592+00:00",
    "path": "/login",
    "status": 400,
    "error": "Bad Request",
    "message": "Request body is missing: public reactor.core.publisher.Mono<org.springframework.http.ResponseEntity<com.ostrozlik.taskagent.web.dto.TokenDto>> com.ostrozlik.taskagent.web.controller.UserController.login(reactor.core.publisher.Mono<com.ostrozlik.taskagent.web.dto.UserDto>)",
    "requestId": "defc8953-1",
    "trace": "org.springframework.web.server.ServerWebInputException: 400 BAD_REQUEST \"Request body is missing: public reactor.core.publisher.Mono<org.springframework.http.ResponseEntity<com.ostrozlik.taskagent.web.dto.TokenDto>> com.ostrozlik.taskagent.web.controller.UserController.login(reactor.core.publisher.Mono<com.ostrozlik.taskagent.web.dto.UserDto>)\"\n\tat org.springframework.web.reactive.result.method.annotation.AbstractMessageReaderArgumentResolver.handleMissingBody(AbstractMessageReaderArgumentResolver.java:230)\n\tSuppressed: reactor.core.publisher.FluxOnAssembly$OnAssemblyException: \nError has been observed at the following site(s):\n\t|_ checkpoint ⇢ Handler com.ostrozlik.taskagent.web.controller.UserController#login(Mono) [DispatcherHandler]\n\t|_ checkpoint ⇢ org.springframework.security.web.server.authorization.AuthorizationWebFilter [DefaultWebFilterChain]\n\t|_ checkpoint ⇢ org.springframework.security.web.server.authorization.ExceptionTranslationWebFilter [DefaultWebFilterChain]\n\t|_ checkpoint ⇢ org.springframework.security.web.server.authentication.logout.LogoutWebFilter [DefaultWebFilterChain]\n\t|_ checkpoint ⇢ org.springframework.security.web.server.savedrequest.ServerRequestCacheWebFilter [DefaultWebFilterChain]\n\t|_ checkpoint ⇢ org.springframework.security.web.server.context.SecurityContextServerWebExchangeWebFilter [DefaultWebFilterChain]\n\t|_ checkpoint ⇢ org.springframework.security.web.server.context.ReactorContextWebFilter [DefaultWebFilterChain]\n\t|_ checkpoint ⇢ org.springframework.security.web.server.header.HttpHeaderWriterWebFilter [DefaultWebFilterChain]\n\t|_ checkpoint ⇢ org.springframework.security.config.web.server.ServerHttpSecurity$ServerWebExchangeReactorContextWebFilter [DefaultWebFilterChain]\n\t|_ checkpoint ⇢ org.springframework.security.web.server.WebFilterChainProxy [DefaultWebFilterChain]\n\t|_ checkpoint ⇢ HTTP POST \"/login\" [ExceptionHandlingWebHandler]\nStack trace:\n\t\tat org.springframework.web.reactive.result.method.annotation.AbstractMessageReaderArgumentResolver.handleMissingBody(AbstractMessageReaderArgumentResolver.java:230)\n\t\tat org.springframework.web.reactive.result.method.annotation.AbstractMessageReaderArgumentResolver.lambda$readBody$5(AbstractMessageReaderArgumentResolver.java:194)\n\t\tat reactor.core.publisher.MonoErrorSupplied.subscribe(MonoErrorSupplied.java:70)\n\t\tat reactor.core.publisher.Mono.subscribe(Mono.java:4219)\n\t\tat reactor.core.publisher.FluxSwitchIfEmpty$SwitchIfEmptySubscriber.onComplete(FluxSwitchIfEmpty.java:75)\n\t\tat reactor.core.publisher.Operators$MultiSubscriptionSubscriber.onComplete(Operators.java:2016)\n\t\tat reactor.core.publisher.MonoFlatMap$FlatMapMain.onComplete(MonoFlatMap.java:174)\n\t\tat reactor.core.publisher.FluxContextStart$ContextStartSubscriber.onComplete(FluxContextStart.java:115)\n\t\tat reactor.core.publisher.FluxMapFuseable$MapFuseableConditionalSubscriber.onComplete(FluxMapFuseable.java:336)\n\t\tat reactor.core.publisher.FluxFilterFuseable$FilterFuseableConditionalSubscriber.onComplete(FluxFilterFuseable.java:384)\n\t\tat reactor.core.publisher.Operators$MonoSubscriber.complete(Operators.java:1783)\n\t\tat reactor.core.publisher.MonoCollect$CollectSubscriber.onComplete(MonoCollect.java:152)\n\t\tat reactor.core.publisher.FluxMap$MapSubscriber.onComplete(FluxMap.java:136)\n\t\tat reactor.core.publisher.FluxPeek$PeekSubscriber.onComplete(FluxPeek.java:252)\n\t\tat reactor.core.publisher.FluxMap$MapSubscriber.onComplete(FluxMap.java:136)\n\t\tat reactor.core.publisher.Operators.complete(Operators.java:135)\n\t\tat reactor.netty.channel.FluxReceive.startReceiver(FluxReceive.java:294)\n\t\tat reactor.netty.channel.FluxReceive.lambda$subscribe$2(FluxReceive.java:138)\n\t\tat io.netty.util.concurrent.AbstractEventExecutor.safeExecute(AbstractEventExecutor.java:164)\n\t\tat io.netty.util.concurrent.SingleThreadEventExecutor.runAllTasks(SingleThreadEventExecutor.java:472)\n\t\tat io.netty.channel.epoll.EpollEventLoop.run(EpollEventLoop.java:384)\n\t\tat io.netty.util.concurrent.SingleThreadEventExecutor$4.run(SingleThreadEventExecutor.java:989)\n\t\tat io.netty.util.internal.ThreadExecutorMap$2.run(ThreadExecutorMap.java:74)\n\t\tat io.netty.util.concurrent.FastThreadLocalRunnable.run(FastThreadLocalRunnable.java:30)\n\t\tat java.base/java.lang.Thread.run(Thread.java:832)\n"
}

Answer 1

可以这样做，不会订阅用户两次。

public Mono<TokenDto> generateToken(Mono<UserDto> user) {
    return user
        .flatMap(userDto ->
            userRepository
                .findByEmail(userDto.getEmail())
                //filter is inside flatmap
                .filter(foundUser -> bCryptPasswordEncoder.matches(userDto.getPassword(), foundUser.getPassword()))
        )
        .map(foundUser -> JWT.create()
            .withSubject(foundUser.getEmail())
            .withExpiresAt(new Date(System.currentTimeMillis() + jwtTtl.toMillis()))
            .withClaim(USER_ROLES_CLAIM, foundUser.getRoles().stream().map(RoleEnum::name).collect(Collectors.toList()))
            .sign(Algorithm.HMAC512(jwtSecret))
        )
        .map(TokenDto::new);
}

Answer 2

这就是我使用zip 所能想到的。为什么你认为在tuple2 结构中使用Mono 是不对的？

public Mono<TokenDto> generateToken(Mono<UserDto> user) {

        return Mono.zip(user,user.flatMap(a -> userRepository.findByEmail(a.getEmail())))
                   .filter(tuple2 -> bCryptPasswordEncoder.matches(tuple2.getT1().getPassword(), tuple2.getT2().getPassword()))
                   .map(tuple2 -> tuple2.getT2())
                   .map(foundUser -> {//your mapping logic})
                   .map(TokenDto::new);

    }