将列表传递给 javax.persistent.query 对象时出现异常答案

【问题标题】：Exception while passing a list to javax.persistent.query object将列表传递给 javax.persistent.query 对象时出现异常
【发布时间】：2014-07-19 01:10:14
【问题描述】：

我有疑问

"SELECT I.INDIVIDUAL_CASE_ID,D.ASSISTER_ID,I.FIRSTNAME,I.LASTNAME,D.LAST_UPDATE_TIMESTAMP,I.ELIGIBILITY_STATUS,I.INDIVIDUAL_CASE_ID," +
               "I.NUMBEROFHOUSEHOLDMEMBERS,I.HOUSEHOLD_INCOME FROM  EXTERNAL_INDIVIDUAL I, EE_DESIGNATE_ASSISTERS D " +
               "WHERE I.INDIVIDUAL_CASE_ID = D.INDIVIDUAL_ID AND D.ASSISTER_ID=:assisterId AND D.INDIVIDUAL_ID IN (:individualIds)";

我正在传递参数，例如

query = em.createNativeQuery(queryStr);
query.setParameter("assisterId", assisterId);
query.setParameter("individualIds",indvIdList);

但是我遇到了异常

SEVERE: Servlet.service() for servlet [appServlet] in context with path [/ghix-entity] threw exception [Request processing failed; nested exception is
java.lang.IllegalArgumentException: org.hibernate.QueryParameterException: could not locate named parameter [individualIds]] with root cause
org.hibernate.QueryParameterException: could not locate named parameter [individualIds]
    at org.hibernate.engine.query.ParameterMetadata.getNamedParameterDescriptor(ParameterMetadata.java:101)

【问题讨论】：

您使用本机查询而不是可能支持接受参数集合的 JPQL 查询的任何原因？

标签： sql oracle hibernate jpa

【解决方案1】：

这是我的问题。我错误地在查询对象中设置了一些额外的参数。删除列表后工作正常。感谢您的所有建议

【讨论】：

【解决方案2】：

如果您使用 Hibernate 而不是其他 JPA 实现：

您可以从 entityManager 获取 Hibernate Session：

Session session = entityManager.unwrap(Session.class);

然后you can use named parameters:

List result = 
    session.createSQLQuery(
            "SELECT I.INDIVIDUAL_CASE_ID,D.ASSISTER_ID,I.FIRSTNAME,I.LASTNAME,D.LAST_UPDATE_TIMESTAMP,I.ELIGIBILITY_STATUS,I.INDIVIDUAL_CASE_ID," +
                    "I.NUMBEROFHOUSEHOLDMEMBERS,I.HOUSEHOLD_INCOME FROM  EXTERNAL_INDIVIDUAL I, EE_DESIGNATE_ASSISTERS D " +
                    "WHERE I.INDIVIDUAL_CASE_ID = D.INDIVIDUAL_ID AND D.ASSISTER_ID=:assisterId AND D.INDIVIDUAL_ID IN (:individualIds)"
    )
    .setLong("assisterId", assisterId)
    .setParameterList("individualIds", indvIdList)
    .list();

【讨论】：

【解决方案3】：

本机查询无法识别命名参数。请看下面的链接似乎类似的问题：JPA/Hibernate Native Queries do not recognize Parameters

尝试： "SELECT I.INDIVIDUAL_CASE_ID,D.ASSISTER_ID,I.FIRSTNAME,I.LASTNAME,D.LAST_UPDATE_TIMESTAM‌P,I.ELIGIBILITY_STATUS,I.INDIVIDUAL_CASE_ID," + "I.NUMBEROFHOUSEHOLDMEMBERS,I.HOUSEHOLD_INCOME FROM EXTERNAL_INDIVIDUAL I, EE_DESIGNATE_ASSISTERS D " + "WHERE I.INDIVIDUAL_CASE_ID = D.INDIVIDUAL_ID AND D.ASSISTER_ID=?1 AND D.INDIVIDUAL_ID IN (?2)";

query = em.createNativeQuery(queryStr); 
query.setParameter(1, assisterId); 
query.setParameter(2,indvIdList);

【讨论】：