SpringInputGeneralFieldTagProcessor 中的 Spring Thymeleaf TemplateProcessingException答案

【问题标题】：Spring Thymeleaf TemplateProcessingException in SpringInputGeneralFieldTagProcessorSpringInputGeneralFieldTagProcessor 中的 Spring Thymeleaf TemplateProcessingException
【发布时间】：2018-06-29 18:19:29
【问题描述】：

我在控制器方法中创建：

@RequestMapping(value = "/user/registration", method = RequestMethod.GET)
    public String showRegistrationForm(WebRequest request, Model model) {
        UserDto userDto = new UserDto();
        model.addAttribute("user", userDto);
        return "registration";
    }

当我转到 URL localhost:8080/user/registration SpringInputGeneralFieldTagProcessor throw TemplateProcessingException 。

org.thymeleaf.exceptions.TemplateProcessingException：期间出错处理器的执行 'org.thymeleaf.spring4.processor.SpringInputGeneralFieldTagProcessor' （模板：“注册” - 第 12 行，第 36 列）

如何解决？

registration.html

<!DOCTYPE html>
<html lang="en" xmlns:th="http://www.thymeleaf.org">
<head>
    <meta charset="UTF-8"/>
    <title>Registration page</title>
</head>
<body>
<form name='regForm' th:userDto="${user}" th:action="@{/registration}" enctype="utf8" method="post">
    <table>
        <tr>
            <td>User:</td>
            <td><input type="text" th:field="*{username}"/></td>
        </tr>
        <tr>
            <td>Email:</td>
            <td><input type='email' th:field="*{email}"/></td>
        </tr>

        <tr>
            <td>Password:</td>
            <td><input type='password' th:field="*{password}"/></td>
        </tr>
        <tr>
            <td>Matching password:</td>
            <td><input type='password' th:field="*{matchingPassword}"/></td>
        </tr>
        <tr>
            <td><input name="submit" type="submit" value="submit" /></td>
        </tr>

    </table>
</form>

</body>
</html>

我的 UserDto.java

package com.eve.web.dto;

import com.eve.validation.ValidEmail;
import org.hibernate.validator.constraints.NotEmpty;

import javax.validation.constraints.NotNull;

public class UserDto {
    @NotNull
    @NotEmpty
    private String username;


    @NotNull
    @NotEmpty
    private String password;

    private String matchingPassword;

    @ValidEmail
    @NotNull
    @NotEmpty
    private String email;


    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public String getMatchingPassword() {
        return matchingPassword;
    }

    public void setMatchingPassword(String matchingPassword) {
        this.matchingPassword = matchingPassword;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }
}

【问题讨论】：

将 th:userDto="${user}" 替换为 th:objet="${user}" 然后使用 th:field="*{username}" 。它工作正常。

标签： java spring spring-boot thymeleaf

【解决方案1】：

由于您使用的是用户，因此您应该将所有属性添加到用户。

在这里你会找到工作代码 `

<!DOCTYPE html>
<html lang="en" xmlns:th="http://www.thymeleaf.org">
<head>
    <meta charset="UTF-8"/>
    <title>Registration page</title>
</head>
<body>
<form name='regForm' th:userDto="${user}" th:action="@{/registration}" enctype="utf8" method="post">
    <table>
        <tr>
            <td>User:</td>
            <td><input type="text" th:field="*{user.username}"/></td>
        </tr>
        <tr>
            <td>Email:</td>
            <td><input type='email' th:field="*{user.email}"/></td>
        </tr>

        <tr>
            <td>Password:</td>
            <td><input type='password' th:field="*{user.password}"/></td>
        </tr>
        <tr>
            <td>Matching password:</td>
            <td><input type='password' th:field="*{user.matchingPassword}"/></td>
        </tr>
        <tr>
            <td><input name="submit" type="submit" value="submit" /></td>
        </tr>

    </table>
</form>

</body>
</html>

【讨论】：