使用 Aws postgres 的 Spring Boot

Question

我正在创建一个项目 Java Springboot，其中 postgreSql 连接到 AWS

一个错误： 白标错误页面 此应用程序没有配置错误视图，因此您将其视为后备。

2021 年 8 月 13 日星期五 10:46:24 UTC [a93e3797-1] 出现意外错误（类型=未找到，状态=404）。

用户控制器：

@RestController
public class UserController {

    @Autowired
    private userService userService;
    private static final String ERROR_MAPPING = "/error";


    @PostMapping(path="/employees")
    public customers addEmployee(@RequestBody customers employee) {
        return userService.save(employee);
    }


    @GetMapping(path="/employees")
    public ResponseEntity<List<customers>> getAllEmployees() {

        return ResponseEntity.ok(userService.listAll());
    }


}

用户服务：

@Service
public class userService {

    @Autowired
    private userRepository repo;

    public List<customers> listAll(){
        return repo.findAll();

    }

    public customers save(customers u) {
        repo.save(u);
        return u;
    }


}

用户存储库：

@Repository
public interface userRepository extends JpaRepository<customers, Long> {
}

用户模型：

@Entity
@Table(name = "customers")
public class customers {

    private int Customer_Id;
    private String First_Name;
    private String Last_Name;
    private int Phone_Number;


 public customers(int customer_Id, String first_Name, String last_Name, int phone_Number) {
        Customer_Id = customer_Id;
        First_Name = first_Name;
        Last_Name = last_Name;
        Phone_Number = phone_Number;
    }

    public customers() {
    }

    public int getCustomer_Id() {
        return Customer_Id;
    }

    public void setCustomer_Id(int customer_Id) {
        Customer_Id = customer_Id;
    }

    public String getFirst_Name() {
        return First_Name;
    }

    public void setFirst_Name(String first_Name) {
        First_Name = first_Name;
    }

    public String getLast_Name() {
        return Last_Name;
    }

    public void setLast_Name(String last_Name) {
        Last_Name = last_Name;
    }

    public int getPhone_Number() {
        return Phone_Number;
    }

    public void setPhone_Number(int phone_Number) {
        Phone_Number = phone_Number;
    }
}

应用程序：包 com.esdt.user;

@SpringBootApplication
@EntityScan("com.esdt.user.model.*")
@EnableJpaRepositories("com.esdt.user.repository.*")
@ComponentScan(basePackages={ "com.esdt.user.controller.*", "com.esdt.user.service.*" })
public class UserApplication {

    public static void main(String[] args) {
        SpringApplication.run(UserApplication.class, args);
    }

}

属性：

## Spring DATASOURCE (DataSourceAutoConfiguration & DataSourceProperties)
spring.datasource.url=jdbc:postgresql://awswebsite/postgres?allowPublicKeyRetrieval=true&useSSL=false
spring.datasource.username=user
spring.datasource.password=pass

# The SQL dialect makes Hibernate generate better SQL for the chosen database
spring.jpa.properties.hibernate.dialect=org.hibernate.dialect.PostgreSQLDialect

# Hibernate ddl auto (create, create-drop, validate, update)
spring.jpa.hibernate.ddl-auto=create
spring.jpa.hibernate.show-sql=true

Answer 1

我添加了以下内容，它可以工作：

<dependency>
                <groupId>org.projectlombok</groupId>
                <artifactId>lombok</artifactId>
                <optional>true</optional>
            </dependency>

<dependency>
                <groupId>org.springframework.boot</groupId>
                <artifactId>spring-boot-starter-test</artifactId>
                <scope>test</scope>
                <exclusions>
                    <exclusion>
                        <groupId>org.junit.vintage</groupId>
                        <artifactId>junit-vintage-engine</artifactId>
                    </exclusion>
                </exclusions>
            </dependency>