我的编译器告诉我它不能将“void”转换为“string”我理解这意味着什么，但不知道如何修复它[关闭]

Question

这里我试图在随机位置（在RandomPosOne()中定义）实例化定义的GameObject

但是我的编译器说

无法从“void”转换为“string”

public class Enemyspawner : MonoBehaviour
{
    public GameObject Elf;
 
    private void OnCollisionEnter2D(Collision2D collider)
    {
        if (collider.gameObject.CompareTag("SpawnTrigger1"))
        {
            InvokeRepeating((SpawnElfOne()), 2f, 3f);

        }
        void SpawnElfOne()
        {
            Instantiate(Elf, RandomPosOne(), Quaternion.identity);
        }
        
    }

    Vector2 RandomPosOne()
    {
        float x, y;
        x = Random.Range(-8.6f, 8.7f);
        y = Random.Range(3.05f, -3.36f);
        return new Vector2(x, y);
    }

    Vector2 RandomPosTwo()
    {
        float x, y;
        x = Random.Range(-8.8f, 8.8f);
        y = Random.Range(19f, 12.6f);
        return new Vector2(x, y);
    }

}

Answer 1

将本地 void 方法 SpawnElfOne 移出到实例中

并在调用InvokeRepeating时将目标方法名称作为string参数传递

public class Enemyspawner : MonoBehaviour {
    public GameObject Elf;
 
    private void OnCollisionEnter2D(Collision2D collider) {
        if (collider.gameObject.CompareTag("SpawnTrigger1")) {
            InvokeRepeating("SpawnElfOne", 2f, 3f);
        }           
    }

    void SpawnElfOne() {
        Instantiate(Elf, RandomPosOne(), Quaternion.identity);
    }
        
    Vector2 RandomPosOne() {
        float x, y;
        x = Random.Range(-8.6f, 8.7f);
        y = Random.Range(3.05f, -3.36f);
        return new Vector2(x, y);
    }

    Vector2 RandomPosTwo() {
        float x, y;
        x = Random.Range(-8.8f, 8.8f);
        y = Random.Range(19f, 12.6f);
        return new Vector2(x, y);
    }

}