使用带有 @QuerydslPredicate 的 Spring @RestController 来处理带有 ZonedDateTime 参数的 GET

Question

我正在创建一个端点，它将接收日期以在服务器端进行一些过滤。代码如下所示：

@RequestMapping(value = "/invoices", method = RequestMethod.GET, produces = MediaType.APPLICATION_JSON_VALUE)
@Timed
public ResponseEntity<List<Invoice>> getAllInvoices(@QuerydslPredicate(root = Invoice.class) Predicate predicate, Pageable pageable) throws URISyntaxException {
    log.debug("REST request to get a page of Invoices");
    Page<Invoice> page = invoiceService.findAll(predicate, pageable);
    HttpHeaders headers = PaginationUtil.generatePaginationHttpHeaders(page, "/api/invoices");
    return new ResponseEntity<>(page.getContent(), headers, HttpStatus.OK);
}

当我尝试使用此 url 调用端点时：http://localhost:3000/api/invoices?page=0&size=20&sort=id,asc&sort=id&transactionDate=2016-05-09T22:00:00.000Z&transactionDate=2016-05-17T21:59:59.999Z

抛出此异常：

java.time.format.DateTimeParseException: Text '2016-05-09T22:00:00.000Z' could not be parsed at index 10
    at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1949) ~[na:1.8.0_91]
    at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1851) ~[na:1.8.0_91]
    at java.time.ZonedDateTime.parse(ZonedDateTime.java:597) ~[na:1.8.0_91]
    at org.springframework.format.datetime.standard.TemporalAccessorParser.parse(TemporalAccessorParser.java:80) ~[spring-context-4.2.4.RELEASE.jar:4.2.4.RELEASE]
    at org.springframework.format.datetime.standard.TemporalAccessorParser.parse(TemporalAccessorParser.java:47) ~[spring-context-4.2.4.RELEASE.jar:4.2.4.RELEASE]
    at org.springframework.format.support.FormattingConversionService$ParserConverter.convert(FormattingConversionService.java:194) ~[spring-context-4.2.4.RELEASE.jar:4.2.4.RELEASE]
    at org.springframework.core.convert.support.ConversionUtils.invokeConverter(ConversionUtils.java:35) ~[spring-core-4.2.4.RELEASE.jar:4.2.4.RELEASE]
    at org.springframework.core.convert.support.GenericConversionService.convert(GenericConversionService.java:192) ~[spring-core-4.2.4.RELEASE.jar:4.2.4.RELEASE]
    at org.springframework.data.querydsl.binding.QuerydslPredicateBuilder.convertToPropertyPathSpecificType(QuerydslPredicateBuilder.java:217) ~[spring-data-commons-1.11.2.RELEASE.jar:na]
..... etc etc

仅使用 ZonedDateTime 对象解析给定的日期works (on ideone.com)，但好的，其他可能有问题。我在 SO 上发现了这个问题：Using Spring @RestController to handle HTTP GET with ZonedDateTime parameters

@RequestMapping(value = "/invoices", params="action", method = RequestMethod.GET, produces = MediaType.APPLICATION_JSON_VALUE)
@Timed
public ResponseEntity<List<Invoice>> findInvoices(@RequestParam("dt") @DateTimeFormat(iso=ISO.DATE_TIME) ZonedDateTime dt,Pageable pageable) throws URISyntaxException {
    log.debug("REST request to get a page of Invoices");
    Page<Invoice> result = invoiceRepository.findAllByTransactionDate(dt,pageable);
    HttpHeaders headers = PaginationUtil.generatePaginationHttpHeaders(result, "/api/invoices");
    return new ResponseEntity<>(result.getContent(), headers, HttpStatus.OK);
}

请求网址：localhost:8080/api/invoices?action=search&dt=2016-05-13T15:12:33.658Z 达到预期效果..

明显的区别是在请求参数中添加了@DateTimeFormat(iso=ISO.DATE_TIME)。现在我想知道；我如何真正让它与 QueryDslPredicateBuilder 一起工作？我应该以某种方式输入格式吗？

Answer 1

在寻找使用 querydsl 参数绑定的不同方面（使用 > x > 类型的比较）时，我遇到了以下帖子： Can Spring Data REST's QueryDSL integration be used to perform more complex queries?

其中一个答案暗示了以下内容：

确保将 @DateTimeFormat 注释添加到 用户的 dateOfBirth-property 以便 Spring 能够转换 正确地将字符串传入 LocalDate 实例。

这是我的问题的解决方案。我已将 @DateTimeFormat 注释添加到我的模型中，这样：

@DateTimeFormat(iso = ISO.DATE_TIME) 
@Column(name = "transaction_date")
private ZonedDateTime transactionDate;

瞧，它有效。