【发布时间】:2020-05-29 17:10:15
【问题描述】:
from django.conf.urls import url
from django.contrib.auth.views import LoginView
from django.contrib.auth.views import LoginView, LogoutView
from . import views
urlpatterns = [
url(r'^login/$', LoginView, name='login', kwargs={
'template_name': 'accounts/login_form.html',
}),
url(r'^logout/$', LogoutView, name='logout', kwargs={
'next_page': 'login',
}),
url(r'^signup/$', views.signup, name='signup'),
url(r'^signup/$', views.signup, name='signup'),
url(r'^profile/$', views.profile, name='profile'),
]
您好,我已阅读有关此错误的其他帖子,并认为我解决了问题,但我仍然遇到问题。
【问题讨论】:
-
您的任何模式都没有您正在访问的网址。
标签: python django url-pattern loginview