【发布时间】:2011-03-28 14:37:21
【问题描述】:
我在User 和Group 之间找到了OneToMany 关系Group.java
@Entity
public class Group {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String groupid;
@ManyToOne
@JoinColumn(name="USER_FK")
private User user;
...
}
User.java
@Entity
public class User {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String userId;
private String password;
private String fname;
private String lname;
@OneToMany(mappedBy="user", cascade=CascadeType.ALL)
private List<Group> groups;
public void addGroup(Group group){
if(this.groups == null){
this.groups = new ArrayList<Group>();
}
this.groups.add(group);
group.setUser(this);
}
}
所以当我尝试持久化对象时
User user = em.find(User.class, 1L);
user.addGroup(group);
persist(user);
我知道了
Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.0.1.v20100213-r6600): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'GROUP (ID, GROUPID, USER_FK) VALUES (2501, 'fdsaf', 1)' at line 1
Error Code: 1064
Call: INSERT INTO GROUP (ID, GROUPID, USER_FK) VALUES (?, ?, ?)
bind => [2501, fdsaf, 1]
Query: InsertObjectQuery(org.xdrawings.entity.Group@a1c)
如您所见,它尝试插入正确的值,但不知何故将其标记为语法错误。我认为它缺少 GROUP 周围的单引号,但由于它在后台进行查询,我不知道如何修复它。请注意,我对同一项目中的其他实体做了完全相同的事情,并且效果很好。好郁闷!!
【问题讨论】:
-
你的桌子是他们应该的样子吗?
标签: java orm jpa jakarta-ee foreign-keys