org.hibernate.AnnotationException：外键引用的列数错误。应该是 2

Question

我有上面截图中的表格

类的写法如下

@Entity  
public class Object {  
    @Id  
    private int id;  

    private String name;  

    @OneToMany(mappedBy="object",fetch=FetchType.LAZY)  
    private List<ObjectAttribute> attrubuteList;  
}  

@Entity  
public class ObjectAttribute {  
    @Id  
    private int id;  
    @Id  
    @ManyToOne  
    @JoinColumn(name="objectId")  
    private Object object;  
    private String name;  
}  

@Entity  
public class Filter {  
    @Id  
    private int filterId;  
    @ManyToOne  
    @JoinColumn(name="ObjectId")  
    private Object object;  
    private String filterName;  
    @OneToMany(mappedBy="filter")  
    private Set<FilterAttribute> filterValues;  
}  

@Entity  
public class FilterAttribute implements Serializable {  

    @Id  
    private int filterAttrId;  
    @Id  
    @ManyToOne  
    @JoinColumn(name="objectId")  
    private Object object;  
    @Id  
    @ManyToOne  
    @JoinColumn(name="filterId")  
    private Filter filter;  
    @Id  
    @ManyToOne  
    @JoinColumn(name="attributeId")  
    private ObjectAttribute attribute;  

    private String value;  
} 

注意没有添加getter和setter

测试代码如下

List<Object> list = sess.createCriteria(Object.class).list();  
        for(Object ob: list)  
        {  
            System.out.println("Object name : "+ ob.getName());  
            List<ObjectAttribute> attList = ob.getAttrubuteList();  

            for (Iterator iterator = attList.iterator(); iterator.hasNext();) {  
                ObjectAttribute objectAttribute = (ObjectAttribute) iterator  
                        .next();  
                System.out.println(objectAttribute.getName());  
            }  
        }  

我得到以下异常

Caused by: org.hibernate.AnnotationException: A Foreign key refering test.rest.ObjectAttribute from test.rest.FilterAttribute has the wrong number of column. should be 2  
    at org.hibernate.cfg.annotations.TableBinder.bindFk(TableBinder.java:450)  

我知道我应该在 FilterAttribute 类中拥有 2 个属性来保存复合键。但是我们该怎么做呢？

Answer 1

@Entity  
public class ObjectAttribute {  
    @Id  
    private int id;  
    @Id  <------------------------ try to remove this annotation
    @ManyToOne  
    @JoinColumn(name="objectId")  
    private Object object;  
    private String name;  
}  

它认为你的 ObjectAttribute 有 2 个 ids 复合键

更新：如果它真的有复合多列主键，你应该引用两列

Answer 2

您的问题是您为实体指定了多个 ID。您只需要在表示对象主键的字段上添加@Id 注释即可。通过使用@ManyToOne 或@OneToMany 注释字段，Hibernate 会将该字段视为外键，而您无需执行任何操作。如果您删除额外的 @Id 字段，一切都应该开始工作了。

@Entity  
public class Object {  
    @Id  
    private int id;  

    private String name;  

    @OneToMany(mappedBy="object",fetch=FetchType.LAZY)  
    private List<ObjectAttribute> attrubuteList;  
}  

@Entity  
public class ObjectAttribute {  
    @Id  
    private int id;  

    @ManyToOne  
    @JoinColumn(name="objectId")  
    private Object object;  

    private String name;  
}  

@Entity  
public class Filter {  
    @Id  
    private int filterId;  

    private String filterName;  

    @ManyToOne  
    @JoinColumn(name="ObjectId")  
    private Object object;          

    @OneToMany(mappedBy="filter")  
    private Set<FilterAttribute> filterValues;  
}  

@Entity  
public class FilterAttribute implements Serializable {  
    @Id  
    private int filterAttrId;  

    @ManyToOne  
    @JoinColumn(name="objectId")  
    private Object object;  

    @ManyToOne  
    @JoinColumn(name="filterId")  
    private Filter filter;  

    @ManyToOne  
    @JoinColumn(name="attributeId")  
    private ObjectAttribute attribute;
}

Answer 3

如果您想使用复合键，这不是这样做的方法

@Entity  
public class ObjectAttribute {  
    @Id  
    private int id;  
    @Id  
    @ManyToOne  
    @JoinColumn(name="objectId")  
    private Object object;  
    private String name;  
}

您有 2 次标记 @id，因此如果您愿意，您需要删除带有 @IdClass 注释的创建复合键（不建议）。

您需要创建包含 2 个键来保存复合键的类

public class CompositeKey {
    private int id; 
    private Object object;  

    //getters and setter
}

之后，您将在实体中定义键

@Entity  
@IdClass(CompositeKey.class)
public class ObjectAttribute {  
    @Id  
    private int id;  
    @Id  
    @ManyToOne  
    @JoinColumn(name="objectId")  
    private Object object;  
    private String name;  
}

这是类似的东西..但是根据我的经验，这不是最好的东西，甚至不建议使用hibernate，只需找到另一个解决方案来使用它..或者使用他的id

希望有帮助

Answer 4

@Entity  
public class ObjectAttribute {  
@Id  
private int id;  
@Id  
@ManyToOne  
@JoinColumn(name="objectId")  
private Object object;  
private String name;  

}

如果你需要两个@Id，则在实体中只使用一个@Id，然后使用两个列名