【问题标题】:Submit file php soap server提交文件 php soap server
【发布时间】:2016-05-16 16:46:17
【问题描述】:

我正在请求帮助解决我遇到的问题。我正在尝试使用 php SOAP 将文件提交到服务器,但是当我提交时,出现此错误:

Fatal error: Uncaught SoapFault exception: [soap11env:Client.SchemaValidationError] :2:0:ERROR:SCHEMASV:SCHEMAV_ELEMENT_CONTENT: Element '{http://mutalyzer.nl/2.0/services}submitBatchJob': Missing child element(s). Expected is ( {http://mutalyzer.nl/2.0/services}data ). in C:\xampp\htdocs\ngs\submit4.php:31 Stack trace: #0 C:\xampp\htdocs\ngs\submit4.php(31): SoapClient->__call('submitBatchJob', Array) #1 {main} thrown in C:\xampp\htdocs\ngs\submit4.php on line 31

WSDL 描述如下:

submitBatchJob 类型 submitBatchJob

data type base64Binary
process - optional, nillable; type string
argument - optional, nillable; type string
email - optional, nillable; type string

submitBatchJobResponse 类型 submitBatchJobResponse

submitBatchJobResult - optional, nillable; type string

<xs:complexType name="submitBatchJob">
<xs:sequence>
<xs:element name="data" type="xs:base64Binary" />
<xs:element name="process" type="xs:string" minOccurs="0" nillable="true" />
<xs:element name="argument" type="xs:string" minOccurs="0" nillable="true" />
<xs:element name="email" type="xs:string" minOccurs="0" nillable="true" />
</xs:sequence>
</xs:complexType>

这是我的 php 脚本:

<?php
$URL = 'https://mutalyzer.nl/services/?wsdl';
?><!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>Mutalyzer SOAP client</title>
</head>
<body>
<h1>Mutalyzer SOAP client</h1>
<?php
if (isset($_GET['data']) && $_GET['data']) {

    $variant = $_GET['data'];


    $_FILES['data']['name']=$_GET['data'];
    $filename = basename( $_FILES['data']['name']);
    $file = fopen($filename, "r");
    $handle = fread($file,filesize($filename));
    $data = base64_encode($handle);


    $NameChecker=$_GET['process'];
    echo '<h2>Result for '.htmlentities($variant).'</h2>';

   $options = array('features' => SOAP_SINGLE_ELEMENT_ARRAYS);

    $client = new SoapClient($URL);

    $result = $client->submitBatchJob($data, $NameChecker)
                  ->submitBatchJobResult;


print_r($result); 
}

?>

<h2>Submit job data file to MUTALYZER</h2>

<form action="" method="GET" enctype="multipart/form-data">
<p>
Input file:
</p>
<input name="data" type="file" id="data" />
<br/>
  Process :
<input type="text" size="10" name="process" id="process" value="NameChecker"/>
<br/>
  <input type="submit" name="upload" value="Submit" />
</form>

</body>
</html>

有谁知道我做错了什么以及如何更正我的脚本? 非常感谢。

【问题讨论】:

  • 您看到他们的示例 PHP 客户端了吗? mutalyzer.nl/downloads/client-php.php
  • @mkaatman,是的,我已经检查了他们的 PHP 客户端。一开始,我做了一些受他们 php 客户端启发的事情。但是,该数组只占用我的数据文件的最后一行。 WDSL 声明数据必须是 base64Binary 所以这就是我更改源代码的原因。

标签: php file soap server


【解决方案1】:

首先您需要捕获该异常:

 try {
   # some code here that causes a problem, hint: soap11env:Client.SchemaValidationError
    } catch (Exception $e) {
        echo $e->getMessage();
    }

其次,它告诉你错误在哪里:

Element '{http://mutalyzer.nl/2.0/services}submitBatchJob': Missing child element(s). Expected is ( {http://mutalyzer.nl/2.0/services}data ). 

还有:

in C:\xampp\htdocs\ngs\submit4.php:31 Stack trace: #0 C:\xampp\htdocs\ngs\submit4.php(31): SoapClient->__call('submitBatchJob', Array) #1 {main} thrown in C:\xampp\htdocs\ngs\submit4.php on line 31

【讨论】:

  • 我添加了异常,我有这个错误::2:0:ERROR:SCHEMASV:SCHEMAV_ELEMENT_CONTENT: Element '{http://mutalyzer.nl/2.0/services}submitBatchJob': Missing child element(s). Expected is ( {http://mutalyzer.nl/2.0/services}data ). 但我不明白我做错了什么
  • 我也试过这样做,但它只需要我的csv文件的最后一行:$options = array('features' =&gt; SOAP_SINGLE_ELEMENT_ARRAYS); $client = new SoapClient($URL, $options); $data=array(); while(! feof($handle)){ $data = fgetcsv($handle, 0); $result = $client-&gt;submitBatchJob(array('data' =&gt; $data[0], 'process' =&gt;$NameChecker)) -&gt;submitBatchJobResult; print_r(array('data' =&gt; $data, 'process' =&gt;$NameChecker)); }
  • 我没有时间通读文档,但看起来肥皂服务器正在期待一些 base64Binary 代码 https://mutalyzer.nl/soap-api#op.submitBatchJob 并且您正在提交一个数组。如果它接受数组,它要求一些孩子,所以也许你的数组需要是多维的?
  • 感谢您的回复。我找到了解决方案。我确实喜欢这样:$handle = fread($file,filesize($filename)); $data=array(); $data = $handle; 它有效 :)
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