【发布时间】:2013-09-24 06:10:20
【问题描述】:
我有一个getstaffinfo方法,它有3个参数(var_1、connection、filewriter fw),var_1的值是从文本文件中读取的。因此,将根据从文本文件传递的所有 var_1 值多次调用该方法。大约(15000)
public static String getstaffid(String var_1, Connection connection,
FileWriter fw) throws SQLException, Exception
// Create a statement
{
String record = null;
ResultSet rs = null;
Statement stmt = connection.createStatement();
boolean empty = true;
try {
rs = stmt
.executeQuery("select username, firstname, lastname, middlename, street, city, stateorprovince, ziporpostalcode, countryorregion, fax, phone, extension, mobile, pager, title, primaryemail, secondaryemail, officename, description, comments, suspendeddate, userdata, employeeid, createuser, updateuser, createdate, updatedate, employeetype, servicedeskticketnumber, startdate, enddate, manager, businessapprover, technicalapprover, delegate, location, jobcodes, customproperty1, customproperty2, customproperty3, customproperty4, customproperty5, customproperty6, customproperty7, customproperty8, customproperty9, customproperty10 from globalusers where username = '"+ var_1 + "'");
ResultSetMetaData metaData = rs.getMetaData();
int columns = metaData.getColumnCount();
ArrayList<String> records = new ArrayList<String>();
while (rs.next()) {
empty = false;
//record = rs.getString(1) + " " + rs.getString(2) + " " + rs.getString(3) + " " + rs.getString(4) + " " + rs.getString(5) + " " + rs.getString(6) + " " + rs.getString(7) + " " + rs.getString(8) + " " + rs.getString(9) + " " + rs.getString(10) + " " + rs.getString(11) + " " + rs.getString(12) + " " + rs.getString(13) + " " + rs.getString(14) + " " + rs.getString(15) + " " + rs.getString(16) + " " + rs.getString(17) + " " + rs.getString(18) + " " + rs.getString(19) + " " + rs.getString(20) + " " + rs.getString(21) + " " + rs.getString(22) + " " + rs.getString(23) + " " + rs.getString(24) + " " + rs.getString(25) + " " + rs.getString(26) + " " + rs.getString(27) + " " + rs.getString(28) + " " + rs.getString(29) + " " + rs.getString(30) + " " + rs.getString(31) + " " + rs.getString(32) + " " + rs.getString(33) + " " + rs.getString(34) + " " + rs.getString(35) + " " + rs.getString(36) + " " + rs.getString(37) + " " + rs.getString(38) + " " + rs.getString(39) + " " + rs.getString(40) + " " + rs.getString(41) + " " + rs.getString(42) + " " + rs.getString(43) + " " + rs.getString(44) + " " + rs.getString(45) + " " + rs.getString(46) + " " + rs.getString(47);
for (int i = 1; i <= columns; i++) {
String value = rs.getString(i);
records.add(value);
}
for (int j = 0; j < records.size(); j++) {
record = records.get(j) + ",";
}
fw.append(record);
}
/*fw.append(rs.getString(1));
fw.append(',');
fw.append(rs.getString(2));
fw.append(',');
fw.append(rs.getString(3));
fw.append('\n'); */
} finally {
fw.flush();
rs.close();
stmt.close();
}
return record;
}
如您所见,正在执行 47 个值的查询,这些值可能为空,也可能有一些值。
然后我遍历这 47 列,获取值并将其存储到数组列表中。然后我迭代数组列表并使用逗号分隔值将所有值写入字符串记录。写入 csv 文件。
但它不能正常工作。任何意见将不胜感激...
【问题讨论】:
-
你有堆栈跟踪吗?
-
for (int j = 0; i
-
你好,是j
-
你在那个循环中得到了 'i' 而不是 'j'。
-
您需要更精确 - 任何关于“它无法正常工作”的详细信息?