【发布时间】:2017-10-03 14:56:27
【问题描述】:
我正在尝试使用持久性单元在骆驼路线中配置我的 JPA 组件。
我正在使用 EAP 6.4 和 Fuse 6.3。
现在这条路线真的很基本,只是为了让它与我的数据源一起工作:
private UserTransaction userTransaction;
private JpaEndpoint jpaEndpoint;
private JaxbDataFormat jaxbDataFormat;
@Override
public void configure() throws Exception {
// @formatter:off
configureErrorHandling();
configureJpa();
from("timer:startup?repeatCount=1")
.to(jpaEndpoint)
.process(exchange -> {
Exchange ex = exchange;
});
// @formatter:on
}
private void configureJpa() {
// Configure our JaxbDataFormat to point at our 'model' package
EntityManagerFactory entityManagerFactory = null;
try {
userTransaction = InitialContext.doLookup("java:jboss/UserTransaction");
entityManagerFactory = InitialContext.doLookup("java:/UtskicksbegaranOraclePU");
} catch (NamingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
jaxbDataFormat = new JaxbDataFormat();
jaxbDataFormat.setContextPath(UtskicksbegaranRequestOracle.class.getPackage().getName());
// Configure a JtaTransactionManager by looking up the JBoss transaction manager from JNDI
JtaTransactionManager transactionManager = new JtaTransactionManager(userTransaction);
transactionManager.afterPropertiesSet();
// Configure the JPA endpoint to use the correct EntityManagerFactory and JtaTransactionManager
jpaEndpoint = new JpaEndpoint();
jpaEndpoint.setCamelContext(getContext());
jpaEndpoint.setConsumeDelete(false);
jpaEndpoint.setMaximumResults(500);
jpaEndpoint.setQuery(consumerQuery);
jpaEndpoint.setEntityType(UtskicksbegaranRequestOracle.class);
jpaEndpoint.setEntityManagerFactory(entityManagerFactory);
jpaEndpoint.setTransactionManager(transactionManager);
}
这里的问题是,当我在我的服务器上启动它时,这一行:
entityManagerFactory = InitialContext.doLookup("java:/UtskicksbegaranOraclePU"); 抛出javax.naming.NameNotFoundException: UtskicksbegaranOraclePU -- service jboss.naming.context.java.UtskicksbegaranOraclePU
以上代码大部分取自 Jboss 打包的快速入门。
当我在没有使用或配置路由中的 JPA 组件的情况下启动服务器时,我可以访问我的服务器并看到我的持久性单元已在 JNDI 中注册。
这是我的 persistence.xml 的样子:
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="UtskicksbegaranOraclePU" transaction-type="JTA">
<jta-data-source>java:jboss/datasources/xa/utskicksbegaran</jta-data-source>
<class>classes</class>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<property name="hibernate.hbm2ddl.auto" value="validate" />
<property name="hibernate.show_sql" value="true" />
<property name="hibernate.default_schema" value="icc" />
<property name="jboss.entity.manager.factory.jndi.name" value="java:/UtskicksbegaranOraclePU"/>
</properties>
</persistence-unit>
</persistence>
基本上,我想要实现的是从我的数据源进行 XA 事务提取,然后将其分发到不同的队列。
我正在使用 camel-spring 启动路线,这是我的配置:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://camel.apache.org/schema/spring
http://camel.apache.org/schema/spring/camel-spring.xsd>
<camelContext id="camelContext_utskicksbegaran-oracle-adapter" xmlns="http://camel.apache.org/schema/spring">
<packageScan>
<package>se.sjv.integration.camel.hanterautskick</package>
</packageScan>
</camelContext>
</beans>
还有其他方法可以使用 Spring 访问在 persistence.xml 中声明的持久性单元吗?我错过了什么?
【问题讨论】:
标签: java jpa apache-camel persistence jndi