使用 jaxb 在 Java 对象中存储 xml 数据

Question

<?xml version="1.0" encoding="UTF-8"?>
  <filepaths>
    <application_information_ticker>
      <desc>Ticker1</desc>
      <folder_path>../atlas/info/</folder_path>
    </application_information_ticker>
    <document_management_system>
      <desc></desc>
      <folder_path>../atlas/dms/</folder_path>
    </document_management_system>
  </filepaths>

我有一个这样的 xml 文件。我需要使用 JAXB 将此 xml 文件转换为 java 对象。由于嵌套标签，我无法执行该操作。请为此建议我一个解决方案

Answer 1

  DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
  DocumentBuilder builder = factory.newDocumentBuilder();
  InputSource is = new InputSource( new StringReader( xmlString) );
  Document doc = builder.parse( is );

  XPathFactory factory = XPathFactory.newInstance();
  XPath xpath = factory.newXPath();
  xpath.setNamespaceContext(new PersonalNamespaceContext());
  XPathExpression expr = xpath.compile("//src_small/text()");

  Object result = expr.evaluate(doc, XPathConstants.NODESET);
  NodeList nodes = (NodeList) result;
  List<String> list = new ArrayList<String>();
  for (int i = 0; i < nodes.getLength(); i++) {
      list.add (nodes.item(i).getNodeValue());
      System.out.println(nodes.item(i).getNodeValue());