【发布时间】:2016-05-15 16:18:58
【问题描述】:
我正在尝试为应用程序创建一个表单。该表单包含两个edittext 字段和一个提交按钮。无论如何,我在 doInBackground() 下收到“必须从 ui 线程调用方法 getText”错误。
这是我的代码:
package com.example.jinson.myapplication;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import android.content.Intent;
import android.os.AsyncTask;
import android.os.Bundle;
import android.support.design.widget.FloatingActionButton;
import android.support.design.widget.Snackbar;
import android.view.View;
import android.support.design.widget.NavigationView;
import android.support.v4.view.GravityCompat;
import android.support.v4.widget.DrawerLayout;
import android.support.v7.app.ActionBarDrawerToggle;
import android.support.v7.app.AppCompatActivity;
import android.support.v7.widget.Toolbar;
import android.view.Menu;
import android.view.MenuItem;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.widget.EditText;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
public class SubmitUname extends AppCompatActivity {
private EditText editTextName;
private EditText editTextUname;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.submit_uname);
editTextName = (EditText) findViewById(R.id.editName);
editTextUname = (EditText) findViewById(R.id.editUserName);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
DrawerLayout drawer = (DrawerLayout) findViewById(R.id.drawer_layout);
ActionBarDrawerToggle toggle = new ActionBarDrawerToggle(
this, drawer, toolbar, R.string.navigation_drawer_open, R.string.navigation_drawer_close);
drawer.setDrawerListener(toggle);
toggle.syncState();
}
public void insert(View view){
String name = editTextName.getText().toString();
String uname = editTextUname.getText().toString();
insertToDatabase(name,uname);
}
private void insertToDatabase(String name, String uname){
class SendPostReqAsyncTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
String paramUsername = params[0];
String paramAddress = params[1];
String name = editTextName.getText().toString();
String uname = editTextUname.getText().toString();
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("name", name));
nameValuePairs.add(new BasicNameValuePair("uname", uname));
try {
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(
"http://localhost/insert-db.php");
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpClient.execute(httpPost);
HttpEntity entity = response.getEntity();
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
return "success";
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
}
}
SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
sendPostReqAsyncTask.execute(name, uname);
}
}
Android 工作室说方法 getText() 必须按照说明从 UI 线程调用:editTextName.getText().toString();和 editTextUname.getText().toString();可能的解决方案??
我是这个领域的新手,请给我一个解决方案。
【问题讨论】:
-
这个论坛有类似的问题。可能是stackoverflow.com/questions/32568340/…这会帮助你
-
您在方法内创建一个类,您应该在方法外创建 SendPostReqAsyncTask。您无法在 doInBackground 方法中访问 UI 组件。因为这个方法是在工作线程中运行的。
-
你已经通过
name和uname访问了,那你为什么需要再次使用getText().toString()?