我将如何处理并行数组以在 java 中存储不同类型的信息

Question

我有以下任务：

最多可以有十个团队。并行数组用于存储球队名称，以及跟踪胜利、加时赛损失和得分的数量。输入最后一个团队的结果后，程序会以与输入相反的顺序输出每个团队的记录摘要。

注意：“W”计2分，“L”计0分，“O”计1分

示例输入：

   3 //Option number 
Toronto //phrase
   W //letters that loop in a while loop
   W
   L
   O
   W
   O
   W
   N //To close the while loop, "N" is entered
Montreal
   L
   L
   O
   L
   L
   W
   L
   L
   N // To close the while loop, "N" is entered
Vancouver
   W
   W
   O
   O
   L
   N //To close the while loop, "N" is entered
Winnipeg
   L
   L
   L
   W
   O
   O
   W
   W
   W
   W
   W
   W
   W
   Q //To close the while loop and get all the results, "Q" is entered

样本输出（以相反的顺序输出结果）：

Team W O L P //States that first, Team and then Wins, Overtime, Losses, and then points. "W" is 2 points, "O" is 1 point, and "L" is 0 point
Winnipeg 8 2 3 18
Vancouver 2 2 1 6
Montreal 1 1 6 3
Toronto 4 2 1 10

我用选项 2 做了一个类似的任务，不需要使用数组，现在是选项 3，它只需要使用并行数组

选项 2 代码：

else if (option == 2){
            int pointsW = 0;
            int pointsL = 0;
            int pointsO = 0;
            int counter = 0;
            int totalpoints = 0;
            String phrase = keyboard.next();
            while(go){
                String letter = keyboard.next();
                    if (letter.equals("W")){
                    pointsW+=2;
                    }
                    else if (letter.equals("L")){
                    pointsL+=0;
                    }
                    else if (letter.equals("O")){
                    pointsO+=1;
                    }
                    counter++;
                    if (letter.equals("N")){
                        totalpoints = pointsW + pointsL + pointsO;
                        counter--;
                        go = false;
                }
            }
            int counter2 = 0;
            int totalpoints2 = 0;
            int pointsW2 = 0;
            int pointsL2 = 0;
            int pointsO2 = 0;
            String phrase2 = keyboard.next();
                while (go2){
                    String letter = keyboard.next();
                    if (letter.equals("W")){
                    pointsW2+=2;
                    }
                    else if (letter.equals("L")){
                    pointsL2+=0;
                    }
                    else if (letter.equals("O")){
                    pointsO2+=1;
                    }
                    counter2++;
                    if (letter.equals("Q")){
                        counter2--;
                        totalpoints2 = pointsW2 + pointsL2 + pointsO2;
                        go2 = false;
                        }
                    }
                            System.out.println(phrase + " has played "+counter+" games and has earned "+totalpoints+" points");
                            System.out.println(phrase2 + " has played "+counter2+" games and has earned "+totalpoints2+" points");
                    if (totalpoints > totalpoints2){
                        int wins = totalpoints - totalpoints2;
                            System.out.println(phrase + " is in first place by "+ wins + " points");
                    }else{
                        int wins2 = totalpoints2 - totalpoints;
                            System.out.println(phrase2 + " is in first place by "+ wins2 + " points");
            }
        }

如何以与选项 2 相同的想法将并行数组合并到选项 3 中？我对学习并行数组真的很陌生，在网上查找有关它的信息时无法获得任何帮助。

更新

else if (option == 3){
            int teams = 10;
            String phrase[] = new String[teams];
            int wins[] = new int [teams];
            int overtime[] = new int [teams];
            int loss[] = new int [teams];
            int points[] = new int [teams];
            int x;
                for (x = 0; x < teams; x++){
                    phrase[x] = keyboard.next();
                    while (go3){
                        String letter = keyboard.next();
                        if (letter.equals("W")){
                            wins[x]++;
                        }
                        else if (letter.equals("L")){
                            loss[x]++;
                        }
                        else if (letter.equals("O")){
                            overtime[x]++;
                        }
                        else if (letter.equals("N") || letter.equals("Q")){
                        points[x] = wins[x]*2+overtime[x];
                        go3 = false;
                        if (letter.equals("Q")){
                            break;
                            }
                        }
                    }
                }
                    System.out.println("Team W O L P");
                        for (int i = x; i >= 0; i--){
                            System.out.println(phrase[i] + " " + wins[i] + " " + overtime[i] + " " + loss[i] + " " + points[i]);
         }
       }
    }
 }

我得到的错误：

Answer 1

您需要名称、胜利、失败、加时赛和积分的数组。但是，当您了解更多信息时，您可以通过创建自定义类型（例如 Game）来更好地管理它，该类型将具有 name 之类的属性，以及用于记录胜利、失败、加时赛等的 List 类型属性。

import java.util.Scanner;

public class Standings {
    public static void main(String[] args) {

        Scanner keyboard = new Scanner(System.in);
        System.out.print("Enter option: ");
        int option = keyboard.nextInt();

        // Number of teams
        int teams = 10;

        // Array for team names
        String[] teamNames = new String[teams];

        // Array to record total wins for each team
        int[] wins = new int[teams];

        // Array to record total overtimes for each team
        int[] overtimes = new int[teams];

        // Array to record total losses for each team
        int[] losses = new int[teams];

        // Array for team points
        int[] points = new int[teams];

        // Variable to be used as a counter for the number of games
        int x;

        // The program will exit when exit = true
        boolean exit = false;

        if (option == 3) {
            System.out.println("[Enter N to end the game for a team or Q to terminate the program]");
            System.out.println("------------------------------------------------------------------");
            // Input and calculation
            for (x = 0; x < teams && !exit; x++) {
                String letter;
                boolean go = true;

                System.out.print("Enter the name of team " + (x + 1) + ": ");
                teamNames[x] = keyboard.next();
                while (go) {
                    System.out.print("Enter W/L/O for match result: ");
                    letter = keyboard.next();

                    if (letter.equals("W")) {
                        wins[x]++;
                    } else if (letter.equals("O")) {
                        overtimes[x]++;
                    } else if (letter.equals("L")) {
                        losses[x]++;
                    } else if (letter.equals("N") || letter.equals("Q")) {
                        points[x] = wins[x] * 2 + overtimes[x];
                        go = false;
                        if (letter.equals("Q")) {
                            exit = true;
                        }
                    }
                }
            }

            // Output
            System.out.println("Team W O L P");
            for (int i = x - 1; i >= 0; i--) {
                System.out
                        .println(teamNames[i] + " " + wins[i] + " " + overtimes[i] + " " + losses[i] + " " + points[i]);
            }
        }
    }
}

示例运行：

Enter option: 3
[Enter N to end the game for a team or Q to terminate the program]
------------------------------------------------------------------
Enter the name of team 1: One
Enter W/L/O for match result: W
Enter W/L/O for match result: W
Enter W/L/O for match result: L
Enter W/L/O for match result: O
Enter W/L/O for match result: N
Enter the name of team 2: Two
Enter W/L/O for match result: L
Enter W/L/O for match result: L
Enter W/L/O for match result: O
Enter W/L/O for match result: W
Enter W/L/O for match result: Q
Team W O L P
Two 1 1 2 3
One 2 1 1 5